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Marina86 [1]
3 years ago
7

HELP ASAP !!!!!!!!!!!! plz

Mathematics
1 answer:
Allushta [10]3 years ago
8 0

I can't see the attachment.

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The length of a rectangle is 4 meters less than twice the width. If the area of the rectangle is 286 square​ meters, find the di
zaharov [31]

Answer:

W = 13 meters, L = 22 meters

Step-by-step explanation:

5 0
3 years ago
Given, f(x) = 2x + 7<br> Find f(3)
Elina [12.6K]
  • Answer:

<em>f(3) = 13</em>

  • Step-by-step explanation:

<em>f(x) = 2x + 7</em>

<em>replace </em><em>x</em><em> with </em><em>3</em>

<em>f(3) = 2×3 + 7</em>

<em>= 6 + 7</em>

<em>= 13</em>

8 0
4 years ago
Can someone please explain to me how to do this.
JulijaS [17]
Y = x² - 4x + 4
y = 2x - 4

Find intersection of L and C:
x² - 4x + 4 = 2x - 4
x² - 6x + 8 = 0
<span> (x - 2)(x - 4) = 0
x = 2 or x = 4

When x = 2 , y = 2(2) - 4 = 0
When x = 4, y = 2(4) - 4 = 4

Points of intersection = A(2, 0) and B(4, 4)

Find the length of AB:

</span>&#10;\text {Length of AB}=  \sqrt{(4-0)^2 + (4-2)^2} =  \sqrt{16 + 4} = \sqrt{20}  = 4.47 \text{ units}
<span>
Answer: 4.47 units

</span>
4 0
4 years ago
Can someone answer this please
ollegr [7]
The answer is symmetric because it’s equal
7 0
3 years ago
In parallelogram DEFG, DH = x + 5, HF = 2y, GH = 3x – 1, and HE = 5y + 4. Find the values of x and y.
earnstyle [38]
The diagonals of a parallelogram bisect each other.

DH = HF and GH = HE

x + 5 = 2y
3x - 1 = 5y + 4

Solve the first equation for x.
x = 2y - 5

Now substitute 2y - 5 for x in the second equation.

3(2y - 5) - 1 = 5y + 4

6y - 15 - 1 = 5y + 4

6y - 16 = 5y + 4

y = 20

Now substitute 20 for y in the first original equation.

x + 5 = 2y

x + 5 = 2(20)

x + 5 = 40

x = 35

Answer: x = 35 and y = 20
4 0
4 years ago
Read 2 more answers
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