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3 years ago

7

What information does the potential energy diagram reveal about a reaction?

2 answers:

Pie3 years ago

8 0

Answer:

It shows whether the reaction is exothermic or endothermic.

Explanation:

luda_lava [24]3 years ago

7 0

Answer: The energy changes that occur during a chemical reaction can be shown in a diagram called a potential energy diagram, or sometimes called a reaction progress curve. A potential energy diagram shows the change in potential energy of a system as reactants are converted into products.

Explanation:

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the reaction of 50 mL of gas with 50 mL of gas via the equation: Cl2(g) + C2H4(g) ➔ C2H4Cl2 (g) will produce a total of ________

spin [16.1K]

Explanation:

The given data is as follows.

50 ml of $Cl_{2}$ , 50 ml of $C_{2}H_{4}$

And, it is known that at STP 1 mole of a gas occupies 22.4 L. Hence, moles present in 50 ml of gas are as follows.

$\frac{50}{22.4 \times 1000}$ (As 1 L = 1000 ml)

= $2.23 \times 10^{-3}$ moles

So, according to the given equation $2.23 \times 10^{-3}$ moles of $Cl_{2}$ reacts with $2.23 \times 10^{-3}$ moles of $C_{2}H_{4}$ .

Hence, moles of $C_{2}H_{4}Cl_{2}$ is equal to the moles of $C_{2}H_{4}$ and $Cl_{2}$ .

Therefore, moles of $C_{2}H_{4}Cl_{2}$ = $2.23 \times 10^{-3}$ moles

1 mole of $C_{2}H_{4}Cl_{2}$ = 22.4 L

$2.23 \times 10^{-3}$ moles = $22.4 \times 2.23 \times 10^{-3} moles$

= 50 ml of product

Thus, we can conclude that 50 ml of products if pressure and temperature are kept constant.

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4 years ago

An instrument used to separate cell parts according to density is the

grigory [225]

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4 years ago

How many helium atoms are in a 12.0 g sample?

lakkis [162]

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4 years ago

Read 2 more answers

In a room full of air, the air is mainly composed of Nitrogen and Oxygen molecules (both at room temperature). Find (to two sign

zloy xaker [14]

Explanation:

Expression for the $v_{rms}$ speed is as follows.

$v_{rms} = \sqrt{\frac{3kT}{M}}$

where, $v_{rms}$ = root mean square speed

k = Boltzmann constant

T = temperature

M = molecular mass

As the molecular weight of oxygen is 0.031 kg/mol and R = 8.314 J/mol K. Hence, we will calculate the value of $v_{rms}$ as follows.

$v_{rms} = \sqrt{\frac{3kT}{M}}$

= $\sqrt{\frac{3 \times 8.314 J/mol K \times 309.02 K}{0.031 kg/mol}}$

= 498.5 m/s

Hence, $v_{rms}$ for oxygen atom is 498.5 m/s.

For nitrogen atom, the molecular weight is 0.028 kg/mol. Hence, we will calculate its $v_{rms}$ speed as follows.

$v_{rms} = \sqrt{\frac{3kT}{M}}$

= $\sqrt{\frac{3 \times 8.314 J/mol K \times 309.92 K}{0.028 kg/mol}}$

= 524.5 m/s

Therefore, $v_{rms}$ speed for nitrogen is 524.5 m/s.

3 0

3 years ago

What is Ka for HCN(aq) H+(aq)+CN-(aq)?

Ierofanga [76]

HCN is a weak acid, with A Ka = 4.0 x 10-10.

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3 years ago