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andrew-mc [135]
2 years ago
11

-1/5(-2 1/4)= Somebody pleaseee helppp meeeee!

Mathematics
2 answers:
evablogger [386]2 years ago
5 0
9/20 I’m pretty sure
erastova [34]2 years ago
3 0
7/20 I’m not sure but hopes it helps
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Five cards are drawn from a standard 52-card playing deck. A gambler has been dealt five cards—two aces, one king, one 3, and on
Nookie1986 [14]

Answer:

The probability that he ends up with a full house is 0.0083.

Step-by-step explanation:

We are given that a gambler has been dealt five cards—two aces, one king, one 3, and one 6. He discards the 3 and the 6 and is dealt two more cards.

We have to find the probability that he ends up with a full house (3 cards of one kind, 2 cards of another kind).

We know that gambler will end up with a full house in two different ways (knowing that he has given two more cards);

  • If he is given with two kings.
  • If he is given one king and one ace.

Only in these two situations, he will end up with a full house.

Now, there are three kings and two aces left which means at the time of drawing cards from the deck, the available cards will be 47.

So, the ways in which we can draw two kings from available three kings is given by =  \frac{^{3}C_2 }{^{47}C_2}   {∵ one king is already there}

              =  \frac{3!}{2! \times 1!}\times \frac{2! \times 45!}{47!}           {∵ ^{n}C_r = \frac{n!}{r! \times (n-r)!} }

              =  \frac{3}{1081}  =  0.0028

Similarly, the ways in which one king and one ace can be drawn from available 3 kings and 2 aces is given by =  \frac{^{3}C_1 \times ^{2}C_1 }{^{47}C_2}

                                                                   =  \frac{3!}{1! \times 2!}\times \frac{2!}{1! \times 1!} \times \frac{2! \times 45!}{47!}

                                                                   =  \frac{6}{1081}  =  0.0055

Now, probability that he ends up with a full house = \frac{3}{1081} + \frac{6}{1081}

                                                                                    =  \frac{9}{1081} = <u>0.0083</u>.

3 0
3 years ago
Read 2 more answers
3a+3b,for a=2 and b=4
il63 [147K]
3a + 3b, for a=2 and b=4 ... The first thing you'd do would be to plug the numbers in -

3 x 2 + 3 x 4 

Then multiply them -

6 + 12 

Then add - 

18.

So your answer should be 18.

5 0
3 years ago
What is missing in the expression -11xu=33
AleksAgata [21]
The number 3

-11x3=33
5 0
3 years ago
simplify the following expression: (x+7/4x) + (5/x-8) I also attached a photo of the problem if you get confused on how I typed
Gnoma [55]

Answer:

\frac{x^{2}  + 19x - 56}{4 {x}^{2}   - 32x}

Step-by-step explanation:

Start by making the denominators of both fraction the same. This can be done by multiplying one fraction's denominator by the other.

After simplifying and combining the two fractions together, check if the numerator can be factorised such that there is a common factor in the denominator and numerator. In this case, the numerator cannot be factorised.

Lastly, expand the denominator.

\frac{x + 7}{4x}  +  \frac{5}{x - 8}

=  \frac{(x + 7)(x - 8)}{4x(x - 8)}  +  \frac{5(4x)}{4x(x - 8)}

=  \frac{x(x) + x( - 8) + 7(x) + 7( - 8) + 20x}{4x(x - 8)}

=  \frac{ {x}^{2} - 8x + 7x - 56 + 20x }{4x(x - 8)}

=  \frac{ {x}^{2}  + 19x - 56}{4x(x - 8)}

=  \frac{ {x}^{2}  + 19x - 56}{4 {x}^{2}  -  32x}

7 0
2 years ago
a crystal that is 0.12 millimeters long appears to be 60 millimeters long under a microscope what is the power of the microscope
AlladinOne [14]
The power of the microscope is x500
7 0
3 years ago
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