Answer:

Step-by-step explanation:
Given: E, F, G, H denote the three coordinates of the area fenced
To find: coordinates of point H
Solution:
According to distance formula,
length of side joining points  is equal to
 is equal to 
So,

Perimeter of a figure is the length of its outline.

Put 

This is true.
So, the point  satisfies the equation
 satisfies the equation 
So, point H is  .
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Answer:
y= -7 and x= -1
Step-by-step explanation:
To do this, line up the variables so it looks like this...
y-6x=-1
y-3x=-4
The reason why -6x and -3y changes to negative is because that it moved to the other side of the equation.
distribute negative to the bottom equation because the two equations have the same number variable which is y...
y-6x=-1
-y+3x=4
Y cancels out and it will be left with -3x = 3.
X = -1.... plug that in to any of the two equation and you get y = -7.
Hope I helped and have a nice day!!
 
        
             
        
        
        
9514 1404 393
Answer:
   13 in by 51 in
Step-by-step explanation:
The area is the product of the dimensions, so is ...
   663 = x(4x -1)
   4x^2 -x -663 = 0 . . . . . . subtract 663 to put in standard form
Using the quadratic formula, we can find the solutions.
   x = (-(-1) ±√((-1)^2 -4(4)(-663)))/(2(4))
   x = (1 ± √10609)/8 = (1 ±103)/8
Only the positive solution is of any use in this problem, so ...
   x = 104/8 = 13
   4x-1 = 4(13)-1 = 51
The dimensions of the rectangle are 13 inches by 51 inches.
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I find it easiest to solve these using a graphing calculator.
 
        
             
        
        
        
Answer:
-1.3
Hope this helps dont 4get to like and star
-mercury
 
        
                    
             
        
        
        
Answer:

Step-by-step explanation:
Both expressions are examples of the <em>distributive property</em>, which basically says "if I have <em>this </em>many groups of some size and <em>that</em> many groups of the same size, I've got <em>this </em>+ <em>that</em> groups of that size altogether."
To give an example, if I've got <em>3 groups of 5 </em>and <em>2 groups of 5</em>, I've got 3 + 2 = <em>5 groups of 5 </em>in total. I've attached a visual from Math with Bad Drawings to illustrate this idea.
Mathematically, we'd capture that last example with the equation
 . We can also read that in reverse: 3 + 2 groups of 5 is the same as adding together 3 groups of 5 and 2 groups of 5; both directions get us 8 groups of 5. We can use this fact to rewrite the first expression like this:
. We can also read that in reverse: 3 + 2 groups of 5 is the same as adding together 3 groups of 5 and 2 groups of 5; both directions get us 8 groups of 5. We can use this fact to rewrite the first expression like this:  .
.
This idea extends to subtraction too: If we have 3 groups of 4 and we take away 1 group of 4, we'd expect to be left with 3 - 1 = 2 groups of 4, or in symbols:  . When we start with two numbers like 15 and 10, our first question should be if we can split them up into groups of the same size. Obviously, you could make 15 groups of 1 and 10 groups of 1, but 15 is also the same as <em>3 groups of 5</em> and 10 is the same as <em>2 groups of 5</em>. Using the distributive property, we could write this as
. When we start with two numbers like 15 and 10, our first question should be if we can split them up into groups of the same size. Obviously, you could make 15 groups of 1 and 10 groups of 1, but 15 is also the same as <em>3 groups of 5</em> and 10 is the same as <em>2 groups of 5</em>. Using the distributive property, we could write this as  , so we can say that
, so we can say that  .
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