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mojhsa [17]
3 years ago
14

In ΔGHI, g = 2.2 cm, h = 9.4 cm and i=8.5 cm. Find the measure of ∠I to the nearest 10th of a degree.

Mathematics
2 answers:
stiv31 [10]3 years ago
6 0

Answer:

59.6

Step-by-step explanation: DeltaMath

seraphim [82]3 years ago
4 0

Answer: 59.6

Step-by-step explanation:

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PC-CSIL
pav-90 [236]

The equality used is Subtraction property of equality

Option A is correct

Step-by-step explanation:

We need to identify which option best explains or justifies Step 1.

Step 1 is: -c = ax^2 + bx

The given equation is: 0 = ax^2 + bx + c

To get the equation for step 1 we need to subtract c on both sides of equation i.e using subtraction property of equality

0-c = ax^2 + bx + c-c

-c = ax^2 + bx

So, The equality used is Subtraction property of equality

Option A is correct.

Keywords: Solving Quadratic Equations

Learn more about Solving Quadratic Equations at:

  • brainly.com/question/4460262
  • brainly.com/question/7361044
  • brainly.com/question/1414350

#learnwithBrainly

5 0
3 years ago
Sam and Rachel both walk dogs in their neighborhood. Sam charges $15 per walk, plus
bija089 [108]

Answer:

Call of duty. warzone=free

Step-by-step explanation:

you go ps store, you search warzone you click download then you wait how many hours. Then you play! And you dont answer this question :) :)

4 0
3 years ago
Q ÷ 2 -qp ÷ 6; let p = -6 and q = 10
ozzi

Answer:

15

Step-by-step explanation:

1. Plug in the values.

q=10

p=-6

10÷2-(10)(-6)÷6

2. Use PEMDAS.

10÷2+60÷6

5+10

15

5 0
3 years ago
What is the surface area of this square pyramid?
OLEGan [10]
240cm2 is the answer
3 0
2 years ago
Which sum or difference identity would you use to verify that cos (180° - q) = -cos q?
Phantasy [73]

Answer:

\cos (a-b)=\cos a \cos b+\sin a \sin b

Step-by-step explanation:

 Given : \cos (180^{\circ}-q)=-\cos q

We have to write which identity we will use to prove the given statement.

Consider \cos (180^{\circ}-q)=-\cos q

Take left hand side of given expression \cos (180^{\circ}-q)

We know

\cos (a-b)=\cos a \cos b+\sin a \sin b

Comparing , we get, a= 180° and b = q

Substitute , we get,

\cos (180^{\circ}-q)=\cos 180^{\circ}  \cos (q)+\sin q \sin 180^{\circ}

Also, we know \sin 180^{\circ}=0 and \cos 180^{\circ}=-1

Substitute, we get,

\cos (180^{\circ}-q)=-1\cdot \cos (q)+\sin q \cdot 0

Simplify , we get,

\cos (180^{\circ}-q)=-\cos (q)

Hence, use difference identity to  prove the given result.

7 0
3 years ago
Read 2 more answers
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