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3 years ago

I have 3 aplles and 20 oranges how much fruit do i have

Mathematics

2 answers:

RSB [31]3 years ago

5 0

You will have 23 pieces of fruit.

OLEGan [10]3 years ago

3 0

Answer:

23 fruits

20 oranges

+3 aplles

=23

Step-by-step explanation:

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The ___ is the set of outputs for a function.

Wewaii [24]

Answer:

Range

The set of output values is called the range of the function.

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3 years ago

A rectangular pool is 7 feet wide. It is 3 times as long as it is wide.

aliina [53]

Answer:

7x21

Step-by-step explanation:

First, we need to find the length of the pool. Since it is three times as long as it is wide, it is 21 feet long (7 x 3 = 21). That way we can tell that it is 7x21, with a perimeter of 56 feet, and an area of 147 feet squared.

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3 years ago

Given any triangle ABC labeled as shown, the law of sines states that:

AlekseyPX

Answer:

A. The ratios of the sine of the angle to the opposite side are the same.

Step-by-step explanation:

The law of sines is ...

sin(A)/a = sin(B)/b = sin(C)/c

7 0

3 years ago

Read 2 more answers

Solve the following system. x2 + y 2= 25 2x + y = 10 The solution set

anzhelika [568]

Answer: {(5,0), (3,4)}

Step-by-step explanation:

You can apply the Substitution method:

- Solve for y from the second equation.

- Substitute into the first equation and solve for x.

Then:

$y=10-2x$

$x^2+y^2=25\\x^2+(10-2x)^2=25\\$

(Remember that: $(a\±b)^2=a^2\±2ab+b^2$ )

$x^2+(10^2-2(10)(2x)+(2x)^2)=25\\x^2+100-40x+4x^2=25\\5x^2-40x+75=0\\x^2-8x+15=0\\(x-5)(x-3)=0\\\\x=5\\x=3$

Substitute the values obtained into one of the original equation and solve for y:

$2(5)+y=10\\10+y=10\\y=0\\\\2(3)+y=10\\6+y=10\\y=4$

The solution set is: {(5,0), (3,4)}

8 0

3 years ago

An athletics squad trains on a long straight track with dots marked at 10m intervals. The coach sets out cones on some of the do

Sedaia [141]

Answer:

There are 6 ways to run 10 m between two cones of the four cones giving a maximum available distance to run as 60 meters

Step-by-step explanation:

The parameters given are

Distance between two cones = 10 m

Number of cones = 4

Therefore, number of ways to choose two 10 m distances (distance between two cones) from the four cones = $\binom{4}{2}$ = 6

Hence there are only six 10 m distances to run between two cones which gives a maximum distance available to run as 60 m.

8 0

3 years ago