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Lerok [7]
3 years ago
14

In the interval 0º < x < 360°, find the values of x for which tan x= -0.6745

Mathematics
1 answer:
SSSSS [86.1K]3 years ago
7 0
Tan(θ) = 3 tan(θ), 0° ≤ θ ≤ 360°

Solve for θ to the nearest degree.

tan(θ) = 3 tan(θ)

Subtract tan(θ) from both sides:

0 = 2 tan(θ)

Divide by 2 both sides:

tan(θ) = 0

If (x,y) is a point on the terminal ray of θ,

then tan(θ) = y/x = 0, and y = 0.

y = 0 ==> θ = 0°, 180°, or 360° in the interval 0° ≤ θ ≤ 360°.
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