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3 years ago

In the interval 0º < x < 360°, find the values of x for which tan x= -0.6745

1 answer:

7 0

Tan(θ) = 3 tan(θ), 0° ≤ θ ≤ 360°

Solve for θ to the nearest degree.

tan(θ) = 3 tan(θ)

Subtract tan(θ) from both sides:

0 = 2 tan(θ)

Divide by 2 both sides:

tan(θ) = 0

If (x,y) is a point on the terminal ray of θ,

then tan(θ) = y/x = 0, and y = 0.

y = 0 ==> θ = 0°, 180°, or 360° in the interval 0° ≤ θ ≤ 360°.

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3 years ago

Write down the equation of a line that is parallel to the x-axis and passes through (-2, 5).

Rudiy27

Answer:

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3 years ago

Find the value of x if a,b, and c are collinear points an b is between a and c

MakcuM [25]

$\sf Hello!$

• $\sf AB = x + 6$
• $\sf BC = 3x - 5$
• $\sf AC = 36 - x$

$\sf We're \:given\: that \:A,\: B\: and \:C \:are \:Collinear\: points$

$\sf Then,$

$\sf AB + BC = AC$

⇒ $\sf x + 6 + 3x - 5 = 36 - x$

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$\sf Hence,$

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~ $\sf iCarl$

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3 years ago

I still don’t understand can someone give a helping hand?

Fofino [41]

Answer:

Step-by-step explanation:

A, B, C, and D, are all functions. the " { " is saying that those functions can are different at different points. For A the function is $A= -x-2$ when $x< 2$ and then $A=x+4$ when $x\geq -2$ . At the point $x=-2$ you can see that the function on the graph is going in two different directions but it stops at $x=-2$ .

Based on the graph you can see that the line on the left has a slope of -1 and if it kept going it would cross the y-axis at $y=-2$ , therefore the equation for the first line is $y =-x-2$ when $x$

The second line on the right side has a slope of 1 and crosses the y-axis at $y=4$ so the equation for that line is $y=x+4$ when $x\geq -2$ .

The only answer that matches these requirements is A

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3 years ago

One positive number is 9 more than twice another. If their product is 731 find the numbers

Anastaziya [24]

The answer is 361.

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Hope this helped!!

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3 years ago