Inscribed Quadrilateral Theorem says that quadrilateral can be inscribed in a circle if and only if the opposite angles are supplementary.
That means
∠C+∠A=180⁰
∠B+∠D=180⁰
So, ∠C+∠A=180⁰ ---->84 + x = 180 ------> x=180-84=96⁰.
Answer: x=96⁰.
Answer:
(x+9)^2 + (y+1)^2 = 100
Step-by-step explanation:
Since the question says diameter, we know the boundary in a circle. Therefore, we just need to find the center and radius.
The center is the midpoint of the two endpoints on a diameter.
Here, it is (-9, -1).
Therefore, the left part of the equation is (x- -9)^2 + (y - -1)^2 = (x+9)^2 + (y+1)^2.
The radius: sqrt(8^2 + 6^2) = 10
So the equation is (x+9)^2 + (y+1)^2 = 100
The answer is a vertex. Corners of any shape are vertexes
Answer:
(6,-6)
Step-by-step explanation:
well if you count over to the right 6 and down 6 that points would be
(6,-6)
