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3 years ago

12

PLEASE HELP ME I AM ON A TEST . WILL MARK BRAINLIEST

1 answer:

tekilochka [14]3 years ago

5 0

Answer:

A. -2

B. -10

Step-by-step explanation:

Given the equation of the line

$y=\dfrac{1}{2}x-1$

Its slope is $\frac{1}{2}.$

A. Perpendicular line has the slope m, for which

$\dfrac{1}{2}\cdot m=-1\Rightarrow m=-2$

B. The equation of the perpendicular line will be in the form

$y=-2x+b$

This line passes through the point (-6,2), substitute its coordinates into the equation:

$2=-2\cdot (-6)+b\\ \\2=12+b\\ \\b=2-12\\ \\b=-10$

So, y-intecept is -10.

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Please help ASAP! Thanks! For the figures below, assume they are made of semicircles, quarter circles and squares. For each shap

bazaltina [42]

Answer:

Part 1) $A=36(\pi-2)\ cm^2$

Part 2) $P=6(\pi+2\sqrt{2})\ cm$

Step-by-step explanation:

Part 1) Find the area

we know that

The area of the shape is equal to the area of a quarter of circle minus the area of an isosceles right triangle

so

$A=\frac{1}{4}\pi r^{2}-\frac{1}{2}(b)(h)$

we have that the base and the height of triangle is equal to the radius of the circle

$r=12\ cm\\b=12\ cm\\h=12\ cm$

substitute

$A=\frac{1}{4}\pi (12)^{2}-\frac{1}{2}(12)(12)$

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simplify

Factor 36

$A=36(\pi-2)\ cm^2$

Part 2) Find the perimeter

The perimeter of the figure is equal to the circumference of a quarter of circle plus the hypotenuse of the right triangle

<em>The circumference of a quarter of circle is equal to</em>

$C=\frac{1}{4}(2\pi r)=\frac{1}{2}\pi r$

substitute the given values

$C=\frac{1}{2}\pi (12)$

$C=6\pi\ cm$

The hypotenuse of right triangle is equal to (applying the Pythagorean Theorem)

$AC=\sqrt{12^2+12^2}$

$AC=\sqrt{288}\ cm$

simplify

$AC=12\sqrt{2}\ cm$

Find the perimeter

$P=(6\pi+12\sqrt{2})\ cm$

simplify

Factor 6

$P=6(\pi+2\sqrt{2})\ cm$

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3 years ago