F(x) = x²
g(x) = x - 3
g(-2) = (-2) - 3 = -5
f(-5) = (-5)² = 25
Answer : <span>(fog)(-2) = 25</span>
Answer:
The expression for the nth term is Tn = 8n -7
Step-by-step explanation:
Here, we are to find an expression for the nth term of the sequence.
Mathematically, the nth term of an arithmetic sequence can be expressed as;
Tn = a + (n-1)d
for T2, the equation is
a + d = 9
for T4, the equation is
a + 3d = 25
we can substitute the equation of T2 into T4 but we first need to rewrite T4
a + d + 2d = 25
9 + 2d = 25
2d = 25 -9
2d = 16
d = 16/2
d = 8
now since a + d = 9
a = 9-d
a = 9-8
a = 1
So the expression for the nth term would be;
1 + (n-1)8
1 + 8n - 8
= 8n -8+1
= 8n -7
Answer:
Test is Left tailed test
Parameter tested is standard deviation
Step-by-step explanation:
We are given the hypothesis as;
Null hypothesis; H0: σ = 8.6
Alternative hypothesis; H1: σ < 8.6
Where;σ is a constant generally known in statistics as the standard deviation.
Now, it's the alternative hypothesis that will let us know whether this is left tailed, right tailed or two tailed.
Alternative hypothesis says σ < 8.6.
This means that the values of σ that satisfy this hypothesis are less than 8.6 and thus are on the left hand side of 8.6 on a number line. Thus, the shaded region in a normal distribution curve will be on the left.
Thus, it's a left tailed test
Answer:
50%
Step-by-step explanation:
Yes, the bathroom have enough water and shampoo for 35 long haired and 40 short haired members.
<h3>What is inequality?</h3>
Inequality can be define as the relation of equation contains the symbol of ( ≤, ≥, <, >) instead of equal sign in an equation.
For 35 long haired and 40 short haired member.
Put this values in the given equation.
For water 70L+60S < 5600
70 x 35 + 60 x 40
2450+2400
4850 <5600
inequality holds
For shampoo 0.02L+0.01S ≤ 1.50
0.02 x 35 + 0.01 x 40
0.7 + 0.4
1.1 < 1.50
inequality holds
Thus, the bathroom have enough water and shampoo for 35 long haired and 40 short haired members.
Learn more about inequality here:
brainly.com/question/14098842
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