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zheka24 [161]
3 years ago
6

A local zoo has two large snakes. The anaconda is currently 5.23 meters long and grows 1.27 meters every month. The python is 4.

76 meters long and grows 2.04 meters per month. How many months (m) does the zookeeper need to wait for the two snakes to be the same length?
Mathematics
1 answer:
kupik [55]3 years ago
7 0

Answer:

1 months

Step-by-step explanation:

Given

Anaconda

Length = 5.23m

Growth = 1.27m monthly

Python:

Length = 4.76m

Growth = 2.04m monthly

Required

Determine when their length will be equal

First, we need to write equations that determines the growth of each snake in m months.

For both snakes;

Expression = Length + Growth * m

For the Anaconda, the expression is:

5.23 + 1.27 * m

5.23 + 1.27 m --- (1)

For the Python, the expression is

4.76 + 2.04 * m

4.76 + 2.04m ---- (2)

Both snakes will have equal length when both expressions (1 & 2) are equal

4.76 + 2.04m = 5.23 + 1.27 m

Collect Like Terms

2.04m - 1.27 m= 5.23 - 4.76

0.77 m= 0.47

Solve for m

m = \frac{0.47}{0.77}

m = 0.61

<em></em>m = 1<em> --- Approximated</em>

<em>Hence, the zookeeper will wait for 1 month</em>

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