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2 years ago

Find the distance between (6, -7), (3, -5) round your answer to the nearest tenth

Mathematics

1 answer:

saw5 [17]2 years ago

3 0

Answer:

d ≈ 3.6 units

Step-by-step explanation:

calculate the distance d using the distance formula

d = $\sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2 }$

with (x₁, y₁ ) = (6, - 7 ) and (x₂, y₂ ) = (3, - 5 )

d = $\sqrt{(3-6)^2+(-5-(-7))^2}$

= $\sqrt{(-3)^2+(-5+7)^2}$

= $\sqrt{9+2^2}$

= $\sqrt{9+4}$

= $\sqrt{13}$

≈ 3.6 ( to the nearest tenth )

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Darya [45]

Hey there!

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3 years ago

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serg [7]

Answer:

1. M > -7

2. y < -1

3. m < -12

4. k > -2

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2 years ago

Y=3x-1 substitute -3 for x

Brums [2.3K]

The answer should be -10

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3 years ago

Which inequalities are true? Check all that apply. Three-fifths < 0 Four-sixths greater-than one-half Nine-elevenths < 1 T

Kipish [7]

$\frac{3}{5} < 0$

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Solution:

We have to find the inequalities that are true

Option 1

$\frac{3}{5} < 0\\\\0.6 < 0$

0.6 is not less than 0

Thus this inequality is not true

Option 2

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0.667 is greater than 0.5

Thus this inequality is true

Option 3

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0.818 is less than 1

Thus this inequality is true

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3 years ago

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The third system is

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4 0

3 years ago

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