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Assoli18 [71]
3 years ago
10

What can you say about the function that generated the following table of values? O A. the function has no x-intercepts O B. the

function has more than one x-intercept C. not enough information to answer the question O D. the function has exactly one x-intercept
Mathematics
1 answer:
alina1380 [7]3 years ago
8 0

Answer:

c but hrid8sbd s sishdnsos d sisivdks s siebw sid djs sie e ie die did eid did dj die dis sjs shwis. dis s sis sjis djsbd

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(2/3)(-9/8)(-4/5)(-1)
sertanlavr [38]

Answer: -0.6

Step-by-step explanation:

7 0
2 years ago
In a house, there is a small statue in the shape of a cylinder. The cylinder has a diameter of 8 inches and a height of h inches
Kitty [74]

The equation that best represent the volume of the cylinder in cubic inches is V = π4²h.

<h3>What is a cylinder?</h3>

A cylinder is simply a 3-dimensional shape having two parallel circular bases joined by a curved surface.

The volume of a cylinder is expressed as;

V = π × r² × h

Where r is radius of the circular base, h is height and π is constant pi.

Given that;

  • Diameter d = 8in
  • Radius r = d/2 = 8in/2 = 4in
  • Height = h
  • Volume of the cylinder V = ?

V = π × r² × h

V = π × (4)² × h

V = π4²h

Therefore, the equation that best represent the volume of the cylinder in cubic inches is V = π4²h.

Learn more on volume of cylinder here: brainly.com/question/16788902

#SPJ1

3 0
2 years ago
Will mark Brainliest if someone can help me!!!!! (Idk if Prinicipal is right 2-5)
Talja [164]

\bf ~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &\$1500\\ r=rate\to r\%\to \frac{r}{100}\dotfill &0.04\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{annually, thus once} \end{array}\dotfill &1\\ t=years\dotfill &1,2,3,4,5 \end{cases}

\bf A=1500\left(1+\frac{0.04}{1}\right)^{1\cdot 1}\implies A=1500(1.04)^1\implies A\approx 1560\\\\\\A=1500\left(1+\frac{0.04}{1}\right)^{1\cdot 2}\implies A=1500(1.04)^2\implies A\approx 1622.4\\\\\\A=1500\left(1+\frac{0.04}{1}\right)^{1\cdot 3}\implies A=1500(1.04)^3\implies A\approx 1687.3\\\\\\A=1500\left(1+\frac{0.04}{1}\right)^{1\cdot 4}\implies A=1500(1.04)^4\implies A\approx 1754.79\\\\\\A=1500\left(1+\frac{0.04}{1}\right)^{1\cdot 5}\implies A=1500(1.04)^5\implies A\approx 1824.98

6 0
3 years ago
Solve using elimination.<br><br> –9x + 9y = 18<br> –6x + 9y = –12
Arada [10]
You can multiply either the top or bottom equation by -1 so lets say you apply it to the bottom equation it’ll look like this:

-9x + 9y = 18
6x - 9y = 12

then the +9y and -9y will cancel out

-9x = 18
6x =12

then you add the two equations together

-3x = 30

divide both sides by -3

x = -10
8 0
3 years ago
Read 2 more answers
██████▓█████▓▓╬╬╬╬╬╬╬╬▓███▓╬╬╬╬╬╬╬▓╬╬▓█ ████▓▓▓▓╬╬▓█████╬╬╬╬╬╬███▓╬╬╬╬╬╬╬╬╬╬╬╬╬█ ███▓▓▓▓╬╬╬╬╬╬▓██╬╬╬╬╬╬▓▓╬╬╬╬╬╬╬╬╬╬╬╬╬╬▓█ ████▓▓
kakasveta [241]

i can't really see the image but i'm sure it's pretty cool (:

8 0
3 years ago
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