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mezya [45]
3 years ago
8

X – y +z = 5 x + y + 2z = 19 x + y + z = 15

Mathematics
1 answer:
otez555 [7]3 years ago
8 0

Answer:

x=5,y=5,z=5

Step-by-step explanation:

x=15-y-z

15-y-z-y+z=5

15-2y=5

y=5

x+y+z=15

15-2y+y+z=15

15-10+5+z=15

z=5

x-y+z=5

x-5+5=5

x=5

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What's 5m²+5m+9m+8m²-m²= plss​
NISA [10]

Answer:

12m^2+14m

Step-by-step explanation:

The "^means exponet" Hope I made your day

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6 0
3 years ago
Read 2 more answers
I need blank 1 and blank 2
lord [1]

Answer:

Blank 1: 40

Blank 2: 10

Step-by-step explanation:

You can start by representing the speed of the water as x and the speed of the dolphin as y, and writing an equation.

y+x=50

y-x=30

Adding these two equations together, you get:

2y=80

y=40 for the speed of the dolphin in still water. Now, you an use one of the previous equations to find the speed of the current.

40-x=30

x=10

Hope this helps!

8 0
3 years ago
Which shows the correct substitution of the values a b and c from the equation -2 equals negative X Plus x squared minus 4 into
kondor19780726 [428]
-2=-x+x square-4
firstly regroup the equation
x square-2x+x-2=0
x square-x-2=0
multiply the first term by the last term.(I.e x square multiply by -2=-2x square)
product of factor = -2x 1
sum of factor= -2x+1(x)= -1
x square -2x+x-2=0
open the bracket:
x(x-2)+1(x-2)=0
x=1 or x=-2
Therefore; x=-1 or x=2


5 0
4 years ago
What digits can be in the ones place of a number that has 5 as a factor?
Sophie [7]
The digits that can be in the ones place is 1 and 5.... I think.
3 0
3 years ago
Write out the first four terms of the series to show how the series starts. Then find the sum of the series or show that it dive
Nostrana [21]

Answer:

The first four terms of the series are

(9+3),(\frac97+\frac35),(\frac9{7^2}+\frac3{5^2}),(\frac9{7^3}+\frac3{5^3})

\sum_{n=0}^\infty \frac9{7^n}+\frac{3}{5^n} = 14.25

Step-by-step explanation:

We know that

Sum of convergent series is also a convergent series.

We know that,

\sum_{k=0}^\infty a(r)^k

If the common ratio of a sequence |r| <1 then it is a convergent series.

The sum of the series is \sum_{k=0}^\infty a(r)^k=\frac{a}{1-r}

Given series,

\sum_{n=0}^\infty \frac9{7^n}+\frac{3}{5^n}

=(9+3)+(\frac97+\frac35)+(\frac9{7^2}+\frac3{5^2})+(\frac9{7^3}+\frac3{5^3})+.......

The first four terms of the series are

(9+3),(\frac97+\frac35),(\frac9{7^2}+\frac3{5^2}),(\frac9{7^3}+\frac3{5^3})

Let

S_n=\sum_{n=0}^\infty \frac{9}{7^n}    and     t_n=\sum_{n=0}^\infty \frac{3}{5^n}

Now for S_n,

S_n=9+\frac97+\frac{9}{7^2}+\frac9{7^3}+.......

    =\sum_{n=0}^\infty9(\frac 17)^n

It is a geometric series.

The common ratio of S_n is \frac17

The sum of the series

S_n=\sum_{n=0}^\infty \frac{9}{7^n}

    =\frac{9}{1-\frac17}

    =\frac{9}{\frac67}

    =\frac{9\times 7}{6}

    =10.5

Now for t_n

t_n= 3+\frac35+\frac{3}{5^2}+\frac3{5^3}+.......

    =\sum_{n=0}^\infty3(\frac 15)^n

It is a geometric series.

The common ratio of t_n is \frac15

The sum of the series

t_n=\sum_{n=0}^\infty \frac{3}{5^n}

    =\frac{3}{1-\frac15}

    =\frac{3}{\frac45}

    =\frac{3\times 5}{4}

    =3.75

The sum of the series is \sum_{n=0}^\infty \frac9{7^n}+\frac{3}{5^n}

                                        = S_n+t_n

                                       =10.5+3.75

                                       =14.25

4 0
3 years ago
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