No because x3•x3•x3= 27x³ and x3•3•3=27x
From the equation we see that the center of the circle is at (-2,3) and the radius is 9.
So using the distance formula we can see if the distance from the center to the point (8,4) is 9 units from the center of the circle...
d^2=(8--2)^2+(4-3)^2 and d^2=r^2=81 so
81=10^2+1^2
81=101 which is not true...
So the point (8,4) is √101≈10.05 units away from the center, which is greater than the radius of the circle.
Thus the point lies outside or on the exterior of the circle...
Answer:
-4/5
Step-by-step explanation:
round you volume measure to a whole number. like if it was 80.4 it would be 80
Let X represent the length of the chord.
By using Pythagoras' Theorem:
4^2 + (X/2)^2 = 15^2
(X^2)/4 = 209
X^2 = 836
X = 28.91
