Answer:
Height of second tower = 17.32m
Step-by-step explanation:
I have attached a diagram depicting the question.
From the diagram, The first tower is depicted by side AEB and the second tower CD.
While d is the distance that separates the two towers and it's given as 15m.
Now, since the angle of depression of the second tower’s base is 60°, then for triangle BAC. Angle C = 60°.
Thus; using trigonometric ratios;
tan 60° = AB/AC.
This gives; AB = d*tan 60°
Similarly, for the triangle BED, BE = d*tan 30°
Since, AE = CD, thus ;
CD = AB − BE
CD = d (tan 60° − tan 30°)
CD = 15(1.7321 − 0.5774)
CD = 15 × 1.1547
CD ≈ 17.32 m.
So, height of second tower = 17.32 m
The Answer to your problem is:
0.66875
Answer:

Step-by-step explanation:

Here in the second term I am considering 2 as power of x .
So rewriting both the terms here:
First term: 12x²y³z
Second term: -45zy³x²
Let us now find out whether they are like terms or not.
"Like terms" are terms whose variables (and their exponents such as the 2 in x²) are the same.
In the given two terms let us find exponents of each variable and compare them for both terms.
z : first and second term both have exponent 1
x: first and second term both have exponent 2
y: first and second term both have exponent 3
Since we have all the exponents equal for both first and second terms variables, so we can say that the two terms are like terms.