Answer:
941 K (668°C)
Explanation:
We have the following data:
Initial pressure : P1 = 1.45 atm
Initial temperature: T1 = 52°C + 273 = 325 K
Final pressure: P2 = 4.2 atm
Final temperature: T2 = ?
The relation between pressure and temperature for a gas at constant volume is given by Gay-Lussac's law:
P1/T1 = P2/T2
That means that the pressure is directly proportional to the absolute temperature (in K). So, we calculate T2 from the equation:
T2 = P2 x T1/P1 = 4.2 atm x (325 K/1.45 atm) = 941 K
Therefore, the final temperature would be 941 K (668°C). This is consistent with the law, that states that if the pressure increase, the temperature will be increased.
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Answer:
P₂ = 1312.9 atm
Explanation:
Given data:
Initial temperature = 25°C
Initial pressure = 1250 atm
Final temperature = 40°C
Final pressure = ?
Solution:
Initial temperature = 25°C (25+273.15= 298.15 K)
Final temperature = 40°C (40+273.15 = 313.15 k)
According to Gay-Lussac Law,
The pressure of given amount of a gas is directly proportional to its temperature at constant volume and number of moles.
Mathematical relationship:
P₁/T₁ = P₂/T₂
Now we will put the values in formula:
1250 atm /298.15 K = P₂/ 313.15 k
P₂ = 1250 atm × 313.15 k / 298.15 K
P₂ = 391437.5 atm. K /298.15 K
P₂ = 1312.9 atm
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