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Svet_ta [14]
3 years ago
10

Right now I’m a freshmen, and we got our scheduling paper for next year as sophomores. I’m wondering if I should take chemistry

or anatomy? Which one and why
Chemistry
2 answers:
Anastasy [175]3 years ago
3 0
Anatomy I think it's important to know anatomy as a young adult so u are self aware of your body
bonufazy [111]3 years ago
3 0
For myself I took chem as a junior and regretted it because I was stuck in a class full of sophomores and so I wish I took chem my sophomore year
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2. How would type of substance affect the rate of reaction?
nasty-shy [4]

Answer: IN terms of the collision theory, increasing the concentration of a reactant increases in the number of collisions between the reacting species per second and therefore increases the reaction rate.

Explanation: hope u get it right

5 0
3 years ago
Why do scientists measure and record the mass of objects rather than their weight?
Zepler [3.9K]
Because the mass is how much of something is in an object, gold and silver can have the same mass but have very different weights.

Hope I helped!

8 0
3 years ago
Give the quantum values of n,l,m and s for nitrogen
sweet [91]
L = 0 to n-1. Hence, it can have values 0, 1, 2. 

<span>m = -l to +l. Hence, it can have values -2, -1, 0, 1, 2 </span>

<span>s = +1/2 and -1/2</span>

4 0
3 years ago
A chemical reaction was carried out by mixing 25 g of pure CaCO3 and 0.75 mole of pure HCl to give CaCl2, H2O and CO2. a. Which
Naily [24]

hola, esta pregunta es bastante difícil pero está bien, no lo sé, lo siento :) :)

4 0
3 years ago
Bob measured out 1.60 grams of sodium. He calculates that 1.60 g of
saul85 [17]

Answer:

84.8%

Explanation:

Step 1: Given data

Bob measured out 1.60 g of Na. He forms NaCl according to the following equation.

Na + 1/2 Cl₂ ⇒ NaCl

According to this equation, he calculates that 1.60 g of sodium should produce 4.07 g of NaCl, which is the theoretical yield. However, he carries out the experiment and only makes 3.45 g of NaCl, which is the real yield.

Step 2: Calculate the percent yield.

We will use the following expression.

%yield = real yield / theoretical yield × 100%

%yield = 3.45 g / 4.07 g × 100% = 84.8%

6 0
3 years ago
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