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Svet_ta [14]
2 years ago
10

Right now I’m a freshmen, and we got our scheduling paper for next year as sophomores. I’m wondering if I should take chemistry

or anatomy? Which one and why
Chemistry
2 answers:
Anastasy [175]2 years ago
3 0
Anatomy I think it's important to know anatomy as a young adult so u are self aware of your body
bonufazy [111]2 years ago
3 0
For myself I took chem as a junior and regretted it because I was stuck in a class full of sophomores and so I wish I took chem my sophomore year
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What element does HgNo​
melisa1 [442]

Answer:

Mercury is a chemical element with symbol Hg and atomic number 80. Classified as a transition metal, Mercury is a liquid at room temperature.

...

Explanation:

3 0
2 years ago
Read 2 more answers
Analysis of skunk spray yields a molecule with 44.77% c, 7.46% h and 47.76% s by mass. what is the empirical formula for this mo
stiv31 [10]
Suppose we have 100 gr of the substance. Then by weight, it would contain 44.77 gr of C, 7.46 gr of H and 47.76 gr of S. We need to look up the atomic weights of these atoms; M_H=1, M_C=12, M_S=32. The following formula holds (where n are the moles of the substance, M its molecular mass and m its mass): n=m/M. Substituting the known quantities for each element, we get that the substance has 3.73 moles of C, 7.46 moles of H and 1.49 moles of S. In the empirical formula for the molecule, all atoms appear an integer amout of times. Hence, for every mole of Sulfur, we have 2.5 moles of C and 5 moles of H (by taking the moles ratios). Thus, for every 2 moles of sulfur, we have 5 moles of C and 10 moles of H. Now that all the coefficients are integer, we have arrived at an empirical formula for the skunk spray agent: C_5H_{10}S_2
4 0
3 years ago
How many grams of Chromium can be formed when 150 grams of
valentinak56 [21]

Answer: 104 g

Explanation: reaction Cr2O3 + 3 H2 ⇒ 2 Cr + 3 H2O

M(Cr2O3) = 150 g/mol, so n = m/M = 1.0 mol

Number of moles of H2 should be 3.0 moles and

It is much greater (150 g / 2.016 g/mol)

1 mol Cr2O3 produces 2 mol Cr.

Mass m= 2.0 mol· 52g/mol= 104 g

6 0
2 years ago
If 25.0 g NO are produced, how many grams of nitrogen gas are used?
ivanzaharov [21]

Based on the assumption that the reaction involves N and O to produce NO, if 25.0 g of NO are produced, the amount of N gas used would be 11.66 grams

<h3>Stoichiometric calculation</h3>

From the equation of the reaction:

       N + O ---------> NO

Mole ratio of N to NO is 1:1

Mole of 25.0 g of NO = 25/30.01 = 0.833 moles

Equivalent mole of N = 0.833 moles

Mass of 0.833 moles N = 0.833 x 14 = 11.66 grams

More on stoichiometric calculations can be found here: brainly.com/question/8062886

7 0
1 year ago
Blank can be made in the field or in the laboratory
Masteriza [31]
It would most likely be a observation or hypothesis
5 0
2 years ago
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