Question

2.

Answer 1

Answer:

C. 500 cm' of 1.0 mol dmº magnesium sulphate solution.

Explanation:

Let us look at each of the solutions individually;

CaCl2  has three particles

K2SO4 has three particles

MgSO4 has two particles

C2H5OH has only one particle

The number of moles of moles in 250 cm of 2.0 mol dm-3 potassium chloride is 250/1000 * 2 = 0.5 moles having two particles

Also; number of moles in 500 cm' of 1.0 mol dm-3 magnesium sulphate solution= 500/1000 * 1 = 0.5 moles having two particles