Answer:
Here is the script:  
function dd = functionDMS(dd)  
prompt= 'Enter angle in DD form ';
dd = input(prompt)
while (~checknum(dd))
if ~checknum(dd)
error('Enter valid input ');
end
dd = input(prompt)
end  
degrees = int(dd)
minutes = int(dd - degrees)
seconds = ( dd - degrees - minutes / 60 ) * 3600  
print degrees
print minutes
print seconds
print dd
Explanation:
The script prompts the user to enter an angle in decimal degree (DD) form. Next it stores that input in dd. The while loop condition checks that input is in valid form. If the input is not valid then it displays the message: Enter valid input. If the input is valid then the program converts the input dd into degrees, minutes and seconds form. In order to compute degrees the whole number part of input value dd is used. In order to compute the minutes, the value of degrees is subtracted from value of dd. The other way is to multiply remaining decimal by 60 and then use whole number part of the answer as minutes. In order to compute seconds subtract dd , degrees and minutes values and divide the answer by 60 and multiply the entire result with 3600. At the end the values of degrees minutes and seconds are printed. In MATLAB there is also a function used to convert decimal degrees to degrees minutes and seconds representation. This function is degrees2dms.
Another method to convert dd into dms is:
data = "Enter value of dd"
dd = input(data)
degrees = fix(dd);
minutes = dd - degrees;
seconds = (dd-degrees-minutes/60) *3600;
 
        
             
        
        
        
Explanation:
when a user changes his or her view to a Report only view when using QuickBooks online they only see a report list page, without having such features as; Navigation panel, Search box or Quick Create (+) icon.
 
        
                    
             
        
        
        
#include <stdio.h>
struct student {
 char firstName[50];
 int roll;
 float marks;
} s[5];
int main() {
 int i;
 printf("Enter information of students:\n");
 // storing information
 for (i = 0; i < 5; ++i) {
 s[i].roll = i + 1;
 printf("\nFor roll number%d,\n", s[i].roll);
 printf("Enter first name: ");
 scanf("%s", s[i].firstName);
 printf("Enter marks: ");
 scanf("%f", &s[i].marks);
 }
 printf("Displaying Information:\n\n");
 // displaying information
 for (i = 0; i < 5; ++i) {
 printf("\nRoll number: %d\n", i + 1);
 printf("First name: ");
 puts(s[i].firstName);
 printf("Marks: %.1f", s[i].marks);
 printf("\n");
 }
 return 0;
}
#◌⑅⃝●♡⋆♡Nåmřāthā ♡⋆♡●⑅◌
 
        
             
        
        
        
You didn't include the original function, but the new function will contain something like:
function kelvin_to_celsius(k) 
{
   return k - 273.15;
}
Depending of course on your programming language.
The outcome for negative Kelvin is undefined, you could test for that.
 
        
                    
             
        
        
        
Given the way computers go about completing a linear search for an array of numbers, we can confirm that it would take about six steps to complete the search. 
<h3>How do computers perform a linear search?</h3>
When given an array of numbers to search through the linear search method, the computer will follow a logical approach. It will begin at the leftmost number, in this case, the number 7, and then compare each number in the array to the number 52, one by one. When the number finally matches the parameter it is searching for, it will return the answer. 
Since in this series of numbers, 52 is the fifth number, the computer will go through the 5 initial steps of comparing each number, and then complete the search with the sixth step which would be returning the index of 52. 
Therefore, we can confirm that it would take about six steps for the computer to complete the search using a linear search. 
To learn more about linear searches visit: 
brainly.com/question/15178888?referrer=searchResults