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Aleksandr-060686 [28]
3 years ago
8

An electrician charges $40 to come to your house. She also chargers $50 for each hour that she works. The electrician charges a

total of $190. How many hours did the electrician work at your house?
A.40x + 50 > 190
B.40 + 50x < 190
C.50x + 40 = 190
D.50x - 40 = 190
Mathematics
2 answers:
stellarik [79]3 years ago
8 0

C if im right because 40 - 190 is 150 and she worked 3 hours 50 50 50 = 150

jasenka [17]3 years ago
4 0

Answer:

3 hours

Step-by-step explanation:

1. $40 - $190 = $150, the electrician charged $40.

2. $150 divided by $50 = 3, since the electrician charges $50 per hour, they stayed for 3 hours.

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A bag with 6 marbles has 2 yellow marbles, 1 blue marble, and 3 red marbles. A marble is chosen from the bag at random. What is
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P = 1/3

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P=\frac{2}{6} =\frac{1}{3}

Hope this helps

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2 years ago
The ratio of girls to boys in the ninth grade is 5:4. if there are 144 boys in the ninth grade, how many girls are there?
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Assume that a simple random sample has been selected from a normally distributed population and test the given claim. Identify t
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Answer:

There is sufficient evidence to conclude that child booster seats meet the specific requirement.

Step-by-step explanation:

Sample: 697, 759, 1266, 621, 569, 432

Formula:

\text{Standard Deviation} = \sqrt{\displaystyle\frac{\sum (x_i -\bar{x})^2}{n-1}}  

where x_i are data points, \bar{x} is the mean and n is the number of observations.  

Mean = \displaystyle\frac{\text{Sum of all observations}}{\text{Total number of observation}}

Mean =\displaystyle\frac{4344}{6} = 724

Sum of squares of differences = 415616

S.D = \sqrt{\frac{415616}{5}} = 288.31

We are given the following in the question:  

Population mean, μ = 1000 hic

Sample mean, \bar{x} = 724

Sample size, n = 16

Alpha, α = 0.05

Sample standard deviation, s = 288.31

First, we design the null and the alternate hypothesis

H_{0}: \mu = 1000\text{ hic}\\H_A: \mu < 1000\text{ hic}

We use one-tailed(left) t test to perform this hypothesis.

Formula:

t_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{\sigma}{\sqrt{n}} }

Putting all the values, we have

t_{stat} = \displaystyle\frac{724 - 1000}{\frac{288.31}{\sqrt{6}} } = -2.344

Now, t_{critical} \text{ at 0.05 level of significance, 5 degree of freedom } = -2.015

Calculation the p-value from table,

P-value = 0.033

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We conclude that the measurement is less than 1000 hic.

Thus, there is sufficient evidence to conclude that child booster seats meet the specific requirement.

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