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3 years ago

30 Points! To Who Ever Can Give Me The Answer

Mathematics

2 answers:

scoundrel [369]3 years ago

6 0

Answer:

the answer is 2

Step-by-step explanation:

12-5(2)=12-10=2

please mark brainliest if you can, it will help me a lot

vampirchik [111]3 years ago

5 0

Answer:

Step-by-step explanation:

12-5(2)

5 times 2 = -10

12-10= 2

You might be interested in

12 is what percentage of 80

PIT_PIT [208]

Answer: " 15 % " .

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→ " 12 is <u> 15% </u> of 80 " .

_______________________________

Step-by-step explanation:

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12 = (n/100) * 80 ;

12 = (80n) /100 ; Solve for "n:

Note: 80/100 = (80/10) / (100/10) = (8/10) = 0.8 ;

12 = (0.8)n ;

↔ (0.8n) = 12

Multiply each side of the equation by "10" ; to get rid of the "decimal" ;

10 * (0.8n) = 10 * 12 ;

to get:

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8n = 120 ;

Divide each side of the equation by "8" ;

to isolate "n" on ONE SIDE of the equation; & to solve for "n" ;

8n/8 = 120/ 8 ;

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to get:

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n = 15 .

_______________________________

Answer: " 15 % " .

_______________________________

→ " 12 is <u> 15% </u> of 80 " .

_______________________________

Hope this helps!

Best wishes!

_______________________________

4 0

3 years ago

Bet u can’t solve this

S_A_V [24]

Answer:

Step-by-step explanation:

Assuming you're solving for p:

$m=2^{-1} *2^p(2^p-1)$

Let $y=2^p$

Now we can re-write the equation with $y$ instead of $2^p$ .

$m=\frac{1}{2} y(y-1)$

$2m=y^2-y$

$y^2-y-2m=0$

Use the quadratic formula to get:

$y = \frac{1+\sqrt{1+8m} }{2}$

$y = \frac{1-\sqrt{1+8m} }{2}$

Therefore, using natural log and log rules:

$2^p = \frac{1+\sqrt{1+8m} }{2}$ , $ln(2^p)= ln(\frac{1+\sqrt{1+8m} }{2})$ , $pln(2) = ln(\frac{1+\sqrt{1+8m} }{2})$ , $p = \frac{ln(\frac{1+\sqrt{1+8m} }{2})}{ln(2)}$

$2^p = \frac{1-\sqrt{1+8m} }{2}$ , $ln(2^p)= ln(\frac{1-\sqrt{1+8m} }{2})$ , $pln(2) = ln(\frac{1-\sqrt{1+8m} }{2})$ , $p = \frac{ln(\frac{1-\sqrt{1+8m} }{2})}{ln(2)}$