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3 years ago

Someone please help.

Mathematics

2 answers:

alexgriva [62]3 years ago

6 0

nonlinear negative association
it’s nonlinear because the points tend to follow a curve, not a line

sweet [91]3 years ago

4 0

The answer would be A

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3 years ago

The Earth’s total diameter is 12700 kilometers, with the solidified, ocean-covered crust that is at its thickest 35 kilometers w

Basile [38]

Answer:

The correct answer is 0.0667 centimeters.

Step-by-step explanation:

Diameter of earth is 12700 kilometers.

Width of the solidified ocean crust is 35 kilometers.

Ratio between the diameter of the earth and the solidified crust is $\frac{12700}{35}$ .

Now the earth is shrunken to a size of a basketball with the diameter as 24.2 centimeters. Let the thickness of the Earth's crust in this model be x centimeters.

Ratio between the diameter of the model earth and the solidified crust is $\frac{24.2}{x}$ .

But this ratio of the real Earth and its model must be equal.

∴ $\frac{12700}{35}$ = $\frac{24.2}{x}$

⇒ x = 0.0667 centimeters.

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3 years ago

Given: C∉ BD ,△ABC D∈ ray BC ,AB=AC=BC Prove: BD>DA>AB

jonny [76]

Triangle ABC is equilateral, because AB=BC=AC=a. Then

m∠A=m∠B=m∠C=60°.

Let point D lie on the ray BC to the right from points B and C and let CD=x. Then BD=a+x, AB=a.

Consider triangle ACD. In this triangle, m∠ACD=180°-m∠ACB=180°-60°=120°.

By the cosine theorem,

$AD^2=AC^2+CD^2-2\cdot AC\cdot CD\cdot \cos \angle ACD,\\\\AD^2=a^2+x^2-2\cdot a\cdot x\cdot \cos 120^{\circ},\\\\AD^2=a^2+x^2+ax,\\\\AD=\sqrt{a^2+x^2+ax}.$

Since $a^2+x^2+ax=a^2+x^2+ax+ax-ax=(a+x)^2-ax,$ then

$AD^2=(a+x)^2-ax$

and

$AD^2=a^2+x^2+ax>a^2=AB^2\Rightarrow AD>AB.$

Therefore, you get double inequality

$AB$ or $BD>AD>AB.$

3 0

3 years ago