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Dmitry [639]
3 years ago
10

How to find area of parallelogram with coordinates of verticles?

Mathematics
1 answer:
ExtremeBDS [4]3 years ago
5 0
You find a parallelogram area by this formula:
A=b\cdot h
Where b is its base and h, its height.
You get b's value applying distance between two points formula.
If A and B points form the base:
A(x_1,y_1)\;\;\;\;B(x_2,y_2) \\  \\ 
d_{AB}= \sqrt{(x_1-x_2)^2+(y_1-y_2)^2} =b

And h is the perpendicular distance between both bases.
You can visit next link to know further about it:
https://www.ck12.org/geometry/Distance-Between-Parallel-Lines/lesson/Distance-Between-Parallel-Lines
-GEOM/

And in attached picture you can find an example in progress you may want to finish.

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Answer:

c. 1.2 * 10^4

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-3x-2=-3(3)-2=-9-2= -11
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"-11", Option "A".

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Which expressions are equivalent to Negative 9 (two-thirds x + 1)? Check all that apply.
Sav [38]

<u><em>Answer:</em></u>

<u><em /></u>-9(\frac{2}{3}x) + 9(1)\\  \\-6x + 9

<u><em>Explanation:</em></u>

<u>Before we begin, remember the following rules:</u>

<u>1- Distribution property:</u>

<u />a(b+c) = ab+ac

<u>2- Simplification of fractions:</u>

<u />\frac{xy}{yz}=\frac{x}{z}

<u>3- Signs in multiplication:</u>

+ve * +ve = +ve

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<u>Now, for the given problem, we have:</u>

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<u />-9 (\frac{2}{3}x +1) =  -9(\frac{2}{3}x) - (-9)(1) = -9(\frac{2}{3}x) + 9(1)

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<u>Now, we simplify the output from the above step:</u>

<u />-9(\frac{2}{3}x) + 9 = \frac{-9*2}{3}x + 9 = -6x+9

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Answer:

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y =  137 degrees.

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