All categories

2 years ago

What are the answer for these I need it ASP its a test its 505 of my grade!!!!!!! PLZ

Mathematics

1 answer:

bixtya [17]2 years ago

6 0

Answer:

I'll do #2 for ya.

a) 27

b) 9

c) 17.5

Step-by-step explanation:

a) 75% of 36 = 27

b) 36-27=9

c) 14*1.25=17.5

You might be interested in

2ND QUESTION. PLEASE PLEASE HELP. 20 POINTS!!!!!!!!ANSWER IN FUL SENTENCES

kupik [55]

Answer:

i dont know what it means but the right image is 4 times larger than the left image

Step-by-step explanation:

6 0

2 years ago

If i- -1, what is the value of ; 3? -1 O i 0 1 0 -

Whitepunk [10]

$i=\sqrt[]{-1}$ $\begin{gathered} i^2=(\sqrt[]{-1})^2 \\ i^2=-1 \end{gathered}$ $\begin{gathered} i^3=i^2\times i \\ i^3=-1\times i \\ i^3=-i \end{gathered}$

5 0

1 year ago

Select all expressions that are equivalent to 5x + (x+6) +3x.

zhuklara [117]

Answer:

9x + 6 and 6x + 6 + 3x

Step-by-step explanation:

6 0

2 years ago

The population of a town is 6500 and is increasing at a rate of 4% each year. Create a function for this scenario. At this rate,

Stella [2.4K]

Answer:

$P_4 = 7604.08$

Step-by-step explanation:

If the population increases at a rate of 4% per annum, then:

In year 1:

$P_1 = P_0 + 0.04P_0$

Where $P_0$ is the initial population and $P_n$ is the population in year n

In year 2

$P_2 = P_1 + 0.04P_1$

It can also be written as:

$P_2 = P_0 + 0.04P_0 + 0.04 (P_0 + 0.04P_0)$

Taking out common factor $P_0$

$P_2 = (1 + 0.04) (P_0) + 0.04P_0 (1 + 0.04)$

Taking out common factor (1 + 0.04)

$P_2 = (1 + 0.04) (P_0 + 0.04P_0)$

Taking out again common factor $P_0$

$P_2 = (1 + 0.04) (1 + 0.04) P_0$

Simplifying

$P_2 = P_0 (1 + 0.04) ^ 2$

$P_n = P_0 (1 + 0.04) ^ n$

This is the equation that represents the population for year n

Then, in 4 years, the population will be:

$P_4 = P_0 (1 + 0.04) ^ 4\\P_4 = 6500(1 + 0.04) ^ 4\\P_4 = 7604.08$

3 0

3 years ago

Find csc 0, sin 0, and cot 0, where is the angle shown in the figure. Give exact values, not decimals approximations. (LISTING B

dexar [7]

Answer:

sup

Step-by-step explanation:

sup

4 0

3 years ago