Write out the sum formula for sin
<span>sin(x + y) = sinxcos + sinycosx </span>
<span>Then expand sin(a + b) + sin(a - b) </span>
<span>sinacosb + sinbcosa + sinacosb - sinbcosa </span>
<span>The 2nd and 4th terms cancel and you get </span>
<span>2sinacosb</span>
In the first quadrant the signs would be (x,y) in the second quadrant they would be (-x,y) in the third (-x,-y) and the fourth (x,-y)
Answer:
11.25
Step-by-step explanation:
Since AB and CD are parallel, ∠D is congruent to ∠A and ∠C is congruent to ∠B. Therefore the two triangles are similar by the AA postulate. Now, the corresponding sides are in proportion
Since AE ↔ DE and AB ↔ CD
So, AE/CD = AB/CD
AE/5 = 9/4
AE = 9(5)/4
= 45/4 = 11.25
Im pretty sure that it would be 600%. If it was 600% that would be 600 over 100 which would be 6
