Answer:
Following are the program in the Python Programming Language.
#define function
def Transfer(S, T):
#set for loop
for i in range(len(S)):
#append in the list
T.append(S.pop())
#return the value of the list
return T
#set list type variable
S = ["a","b","c","d"]
#print the values of the list
print(S)
#set the list empty type variable
T=[]
#call the function
T = Transfer(S, T)
#print the value of T
print(T)
<u>Output:</u>
['a', 'b', 'c', 'd']
['d', 'c', 'b', 'a']
Explanation:
Here, we define the function "Transfer()" in which we pass two list type arguments "S" and "T".
- Set the for loop to append the values in the list.
- Then, we append the value of the variable "S" in the variable "T".
- Return the value of the list variable "T" and close the function.
- Then, set the list data type variable "S" and initialize the elements in it and print that variable.
- Finally, we set the empty list type variable "T" and store the return value of the function "Transfer()" in the variable "T" then, print the value of the variable "T".
computer network is the answer
EOCS can be fixed locations, temporary facilities, or virtual structures with staff participating remotely is a true statement.
<h3>What is the Emergency Operations Centers (EOC)?</h3>
Emergency Operations Centers is known to be part of the four NIMS Command and Coordination structures as the EOCs are known to be used in an off site locations where staff are gotten from a lot of agencies that come together to address some imminent kind of threats and hazards.
Therefore saying that EOCS can be fixed locations, temporary facilities, or virtual structures with staff participating remotely is a true statement.
Learn more about EOCS from
brainly.com/question/10794095
#SPJ1
Answer:
public class num9 {
public static void main(String[] args) {
int sum =0;
int num =5;
for(num =5; num<=500; num+=5){
System.out.println(num);
sum +=num;
}
System.out.println(sum);
}
}
Explanation:
- Declare and initialize the variables sum and num
- Use a for loop with the condition for(num =5; num<=500; num+=5) Since the loop will increment by 5 and run from 5 to 500
- Within the loop, add num to sum at each iteration
- Print all elements on seperate lines
- Outside the loop, print the final value of sum
Create a for loop
Answer:
#include <bits/stdc++.h>
using namespace std;
int main() {
string email,username,host;//strings to store email,username,hostname..
cout<<"Enter the email address "<<endl;
cin>>email;//taking input of email address..
bool flag=1;
for(int i=0;i<email.length();i++)//iterating over the string email..
{
if(email[i]=='@')//if @ symbol is encountered make flag 0 skip this iteration.
{
flag=0;
continue;
}
if(flag==1)//add to username if flag is 1.
{
username+=email[i];
}
else//add tom host..
host+=email[i];
}
cout<<"The username is "<<username<<endl<<"The host name is "<<host;//printing the username and hostname..
return 0;
}
Explanation:
I have taken three strings to store the email address entered by user ,username and host to store username and host name respectively.Then I am iterating over the string email if @ is encountered then skip that iteration before that keep adding characters to username string and after that keep adding characters to host.
