Answer:
Step-by-step explanation:
<h3>sorry butt can you tell me what you need help with</h3>
You can solve the pair of equations graphically by finding where the two lines intersect/meet. The point where they intersect is the solution to both of the equations.
Slope-intercept form: y = mx + b
(m is the slope, b is the y-intercept, or the point where x = 0 ---> (0 , y))
y = 7x - 9
m = 7
y-intercept = -9 -----> (0, -9)
y = 3x - 1
m = 3
y-intercept = -1 ------> (0, -1)
I'm not really sure what the last sentence of the question is asking, so you could clarify the question if you need help
Ln(xy) - 2x =0
slope of the tangent line = derivative of the function
[ln(xy)]' = [2x]'
[1/(xy)] [y + xy'] = 2
y + xy' = 2(xy)
xy' = 2xy - y =y(2x-1)
y' = y(2x-1)/x
Now use x = -1 to find y and after to find y'
ln(xy) = 2x
x=-1
ln(-y) =-2
-y = e^-2
y = - e^-2
y' = [-e^-2][2(-1)-1]/(-1) = [e^-2](-2-1)= [e^-2](-3) = - 3e^-2
Answer: option 6. from the list
Answer:
7.157894736842105263
Step-by-step explanation:
(calculator)
