What is the greatest common factor of 50, 25 and 100

Mathematics

1 answer:

Zina [86]2 years ago

3 0

Answer:

The common factors for 50,25,100 50 , 25 , 100 are −25,−5,−1,1,5,25 - 25 , - 5 , - 1 , 1 , 5 , 25

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Find the values of x and y for which the lines are parallel.

bearhunter [10]

The answer: " x = 68, y = 72 " .
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Explanation:
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46 + (x - 3) + (y - 3) = 180 .

46 + 1(x - 3) + 1(y-3) = 180 .

46 + 1x - 3 + 1y - 3 = 180 .

46 - 3 - 3 + 1x + 1y = 180 .

40 + x + y = 180 ;

Subtract "40" from EACH SIDE of the equation:
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40 + x + y - 40 = 180 - 40 ;

to get:

x + y = 140 ;
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Now:
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65 = (x - 3) ;

↔ x - 3 = 65 ;

Add "3" to EACH SIDE of the equation;

    x - 3 + 3 = 65 + 3 ;

to get:

           x = 68 .
______________________________
Now:

Since: "x + y = 140" ;

Let us plug in our known value, "68" ; for "x" ;

to solve for "y" ;
__________________________________
   x + y = 140 ;

  68 + y = 140 ;

↔ y + 68 = 140 ;

Subtract "68" from EACH SIDE of the equation; to isolate "y" on one side of the equation; and to solve for "y" ;
______________________________________________
   y + 68 - 68 = 140 = 68 ;

                  y = 72 .
______________________________________________
So, solve for "x" and "y".

x = 68, y = 72 .
_______________________________________________

5 0

3 years ago

What is the equation of this parabola in vertex form

attashe74 [19]

first off, let's notice the parabola is a vertical one, therefore the squared variable is the x, and the parabola is opening upwards, meaning the coefficient of x² is positive.

let's notice the vertex, or U-turn, is at (-2, 2)

$\bf ~~~~~~\textit{parabola vertex form} \\\\ \begin{array}{llll} \boxed{y=a(x- h)^2+ k}\\\\ x=a(y- k)^2+ h \end{array} \qquad\qquad vertex~~(\stackrel{-2}{ h},\stackrel{2}{ k}) \\\\\\ y=+1[x-(-2)]^2+2\implies y=(x+2)^2+2$