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Verdich [7]
3 years ago
8

The Lcm of 4,9 what is that

Mathematics
2 answers:
Alexxandr [17]3 years ago
6 0

Answer:

36

Step-by-step explanation:

White raven [17]3 years ago
6 0

Answer:

36

Step-by-step explanation:

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Lines A, B, and C show proportional relationships. Which line has a constant of proportionality between y and x of 4/3
Drupady [299]

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Line B

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Enter the slope of the line through the points (4 , 15) and (4 , 12)​
pentagon [3]

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Step-by-step explanation:

slope m= (y2-y1) / (x2-x1) = 15-12 / 4-4 = 3/0 is undefined since we can not divide by 0

slope is undefined so the line is vertical

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I need help with this problem
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The left side −0

¯4 is greater than the right side−0.¯¯¯¯¯¯6h means that the given statement is always true.

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4 0
3 years ago
Select all the rates that are unit rates.
Nataly_w [17]

Answer:

\frac{2/3}{1} and \frac{3}{1}

Step-by-step explanation:

Options

\frac{1}{1/3}     \frac{2/3}{1}     \frac{2}{3}     \frac{3}{1}     \frac{1}{9}

Required

Select the unit rates

Unit rate involve two items where the first item being measured can be any positive number, but the second item must be measured in units (i.e. 1)

For clarity:

If \frac{a}{b} represents unit rate, then b = 1

Having said that:

Only \frac{2/3}{1} and \frac{3}{1} satisfy the condition of unit rates; others are not because they have a denominator other than 1

3 0
3 years ago
A farmer wants to fence a rectangular area of 72 square feet next to a river. Find the length and width of the rectangle which u
Arlecino [84]

Answer:

  • 12 ft parallel to the river
  • 6 ft perpendicular to the river

Step-by-step explanation:

The least fence is used when half the total fence is parallel to the river. That is, the shape of the rectangle is twice as long as it is wide.

72 = W(2W)

36 = W²

6 = W . . . . . . the width perpendicular to the river

12 = 2W . . . .  the length parallel to the river

_____

<em>Development of this relation</em>

Let T represent the total length of the fence for some area A. Then if x is the length along the river, the width is y=(T-x)/2, and the area is ...

  A = xy = x(T -x)/2

Note that the equation for area is that of a parabola with zeros at x=0 and at x=T. That is, for some fence length T, the area will be a maximum at the vertex of this parabola. That vertex is located halfway between the zeros, at ...

 x = (0 +T)/2 = T/2

The corresponding area width (y) is ...

  y = (T -T/2)/2 = T/4

Equivalently, the fence length T will be a minimum for some area A when x=T/2 and y=T/4. This is the result we used above.

8 0
3 years ago
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