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Ganezh [65]
3 years ago
14

What is 9.545 x 103 in standard notation

Mathematics
1 answer:
WINSTONCH [101]3 years ago
3 0
9.545 x 103 = 983.135
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Please help, i attached a photo.
Xelga [282]

Answer:

yes..

Step-by-step explanation:

3 0
3 years ago
Steph makes 90 % 90%90, percent of the free throws she attempts. She is going to shoot 3 33 free throws. Assume that the results
zmey [24]

Using the binomial distribution, it is found that there is a 0.027 = 2.7% probability that he makes exactly 1 of the 3 free throws.

For each free throw, there are only two possible outcomes, either he makes it, or he misses it. The results of free throws are independent from each other, hence, the binomial distribution is used to solve this question.

Binomial probability distribution

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

C_{n,x} = \frac{n!}{x!(n-x)!}

The parameters are:

  • x is the number of successes.
  • n is the number of trials.
  • p is the probability of a success on a single trial.

In this problem:

  • He makes 90% of the free throws, hence p = 0.9.
  • He is going to shoot 3 free throws, hence n = 3.

The probability that he makes exactly 1 is P(X = 1), hence:

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 1) = C_{3,1}.(0.9)^{1}.(0.1)^{2} = 0.027

0.027 = 2.7% probability that he makes exactly 1 of the 3 free throws.

To learn more about the binomial distribution, you can take a look at brainly.com/question/24863377

3 0
2 years ago
6 through 9, I just need the answers ‍♂️
wariber [46]
The answer is down below following the order 6~9
6. A
7. C
8.C
9. D
3 0
4 years ago
Solve this system of linear equations. Separate
Sladkaya [172]

Step-by-step explanation:

making x subject in eq 1

x= (-1-9y)/-14

substituting the value of x in eq 2

17(-1-9y/-14)=7+9y

(-17-153y)/-14=7+9y

-17-153y=-98-126y

-17+98=153y-126y

81=27y

y=3

substituting this value of y in eq 1

-14x=-1-9(3)

-14x=-28

x=2

(x,y) = (2,3)

8 0
4 years ago
Hello there when i looked for an answer on your site i found it but it was wrong
Ray Of Light [21]
I think you have to email them or something lol
5 0
3 years ago
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