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Anit [1.1K]
2 years ago
5

What is the anwser for 4n-2n=4

Mathematics
1 answer:
nadya68 [22]2 years ago
7 0

Answer:

2

Step-by-step explanation:

4n-2n=4

2n=4

n=4/2

n=2

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Find the sum of the first 325325 positive even whole numbers.
iris [78.8K]
Multiply 325326×(325325/2)=52,918,503,138 How it works:
know that 325325+1 is 325326, then 325324+2 is the same number, therefore you will get this number as many times as half of biggest number since you sum every last biggest number-1 with every last smallest number+1. so just multiply and you will get
6 0
3 years ago
If 72 is 120% of a number, what is 80%<br> of this number?
cupoosta [38]

Answer:

60

Step-by-step explanation:

As we have all the required values we need, Now we can put them in a simple mathematical formula as below:

STEP 172 = 120% × Y

STEP 272 =  

120

100

× Y

Multiplying both sides by 100 and dividing both sides of the equation by 120 we will arrive at:

STEP 3Y = 72 ×  

100

120

STEP 4Y = 72 × 100 ÷ 120

STEP 5Y = 60

Finally, we have found the value of Y which is 60 and that is our answer.

You can easily calculate 72 is 120 percent of what number by using any regular calculator, simply enter 72 × 100 ÷ 120 and you will get your answer which is 60

7 0
2 years ago
M! = 4125. What is m? n! = 281600. What is n?
Oksanka [162]

Step-by-step explanation:

m <u>~</u><u> </u>6.9

6.9! = 4122.7

4122.7 average 4125

<u>n</u><u> </u><u>~</u><u> </u><u>8</u><u>.</u><u>9</u>

8.9! = 289867.7

289867.7 average 281600<u> </u>

4 0
2 years ago
Help please!!!!!!!!!
ozzi
The formula is 3x+14=32.
answer is 6
7 0
3 years ago
Read 2 more answers
Bad gums may mean a bad heart. Researchers discovered that 81% of people who have suffered a heart attack has periodontal diseas
IgorC [24]

Answer:

0.405 or 40.5%

Step-by-step explanation:

Let event A=having a periodontal disease

event B=having a heart attack

we are given

P(A)=P(having a periodontal disease)=0.30

P(B)=P(having a heart attack)=0.15

P(A/B)=P(have a periodontal disease/have a heart attack)=0.81

P(B/A)=P(have a heart attack/have a periodontal disease)=?

P(A/B)=P(A∩B)/P(B)

P(A∩B)=P(B)*P(A/B)=0.15*0.81=0.1215

P(B/A)=P(A∩B)/P(A)=0.1215/0.3=0.405

There is 40.5% probability that if someone has periodontal disease will have a heart attack.

7 0
2 years ago
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