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Elza [17]
3 years ago
13

What is the result of adding 6/100 and 1/10? use forms of a/b​

Mathematics
1 answer:
Oksana_A [137]3 years ago
3 0

Step-by-step explanation:

1/10 is equivalent to saying 10/100.

Adding these together would look like:

10/100 + 6/100 = 16/100 (cannot be simplified)

a/b = 16/100

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URGENT PLEASE SOMEONE I'LL PUT THE BRAINLIEST 5 POINTS AND THAT CROWN
iogann1982 [59]

Answer: so what you would do is would would take the first number that being -2 and add it to the problem like this y=2(-2)+1 and what you do is you times 2 and x2 which give you -4 then you add 1 which gives you -3 so y = -3

Step-by-step explanation:

Y=2(-2)+1               Y=2(-1)+1

-4+1                           -3+1

-3                                -2

y=2(0)+1                 Y=2(1)+1

0+1                             2+1

0                                 3

y=2(2)+1

4+1

5

7 0
2 years ago
The diameter of a circle is 20 centimeters. What is the circumference?
nlexa [21]

Answer:

20\pi cm

Step-by-step explanation:

C = d\pi

C = 20\pi

7 0
2 years ago
Read 2 more answers
Find an equation of variation where y varies directly as x and y = 7 when x = 0.5 .
Alisiya [41]

Answer:

y = 14x

Step-by-step explanation:

Use the direct variation equation, y = kx

Plug in 7 as y and 0.5 as x, and solve for k:

y = kx

7 = k(0.5)

14 = k

Plug this into the equation:

y = kx

y = 14x

So, the equation of variation is y = 14x

4 0
3 years ago
In the diagram of circle C, what is the measure of 21?
kondaur [170]

Answer:

If I know what diagram you're referring to, which I believe I do, the answer is: ∠1=(1/2)[106°-36°]=35°

4 0
3 years ago
Determine as a linear relation in x, y, z the plane given by the vector function F(u, v) = a + u b + v c when a = 2 i − 2 j + k,
Ostrovityanka [42]

Answer:

2x - y - 3z = 0

Step-by-step explanation:

Since the set

{i, j}  = {(1,0), (0,1)}

is a base in \mathbb{R}^2

and F is linear, then

<em>{F(1,0), F(0,1)}  </em>

would be a base of the plane generated by F.

F(1,0) = a+b = (2i-2j+k)+(i+2j+k) = 3i+2k

F(0,1) = a+c = (2i-2j+k)+(2i+j+2k) = 4i-j+3k

Now, we just have to find the equation of the plane that contains the vectors 3i+2k and 4i-j+3k

We need a normal vector which is the cross product of 3i+2k and 4i-j+3k

(3i+2k)X(4i-j+3k) = 2i-j-3k

The equation of the plane whose normal vector is 2i-j-3k and contains the point (3,0,2) (the end of the vector F(1,0)) is given by

2(x-3) -1(y-0) -3(z-2) = 0

or what is the same

2x - y - 3z = 0

3 0
3 years ago
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