$\bf \stackrel{\measuredangle ACP}{(3x+2y)}+\stackrel{\measuredangle BCP}{(3x+4y)}=90\implies 6x+6y=90\implies \stackrel{\textit{common factor}}{6(x+y)}=90
\\\\\\
x+y=\cfrac{90}{6}\implies x+y=15\implies \boxed{x=15-y}
\\\\[-0.35em]
~\dotfill$

$\bf \stackrel{\measuredangle APC}{(7x+3)}+\stackrel{\measuredangle BPC}{(16y)}=180\implies 7x+16y=177\implies 7\left( \boxed{15-y} \right)+16y=177
\\\\\\
105-7y+16y=177\implies 9y=72\implies y=\cfrac{72}{9}\implies \blacktriangleright y=8 \blacktriangleleft
\\\\[-0.35em]
\rule{34em}{0.25pt}\\\\
\measuredangle BPC=16(8)\implies \measuredangle BPC=128$

4 0

3 years ago

2(x + 1) + 4 = 12<br> Help someone please show work. Oh yessssss!

Bingel [31]

Answer:

X=3

Step-by-step explanation:

2(x+1)+4-4=12-4

2(x+1)=8

2(x+1)/2=8/2

x+1=4

x+1-1=4-1

x=3

6 0

3 years ago

Y+16 > 19 or y+9 < 4

kotykmax [81]

Answer:

y<-5 or y>3

Step-by-step explanation:

y+16>19 : y>3

y+9<4 :y <-5

y>3 or y<-5

y<-5 or y>3

6 0

3 years ago