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Mrrafil [7]
3 years ago
13

Oh please i need help lol

Mathematics
1 answer:
drek231 [11]3 years ago
6 0

Answer:

 

Step-by-step explanation:

                               

Download pdf
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When salt and water are combined, they form a salt or saline solution. How much ml of water must be added to 150 mL of an 80% sa
Vinvika [58]

Answer:

We must add 400 ml of water.

Step-by-step explanation:

We can use the following equation:

C_{i}V_{i}=C_{f}V_{f}

Where:

  • C(i) is the initial concentration of the solution (80%)
  • C(f) is the final concentration of the solution (30%)
  • V(i) is the initial volume (150 ml)
  • V(f) is the final volume

Now, we just need to solve the equation for V(f).

V_{f}=\frac{C_{i}V_{i}}{C_{f}}

V_{f}=\frac{80*150}{30}

V_{f}=400\: ml

Therefore, we must add 400 ml of water.

I hope it helps you!

3 0
3 years ago
If MN = x+4 and DE = 3x-2, find x. (More info in pic)
algol [13]

Answer:  D) 10

============================================================

Explanation:

I'm assuming points M and N are midpoints of segments FD and FE respectively. If that's the case, then segment DE is twice as long compared to segment MN. We consider MN to be a midsegment.

So,

DE = 2*(MN)

3x-2 = 2*(x+4)

3x-2 = 2x+8

3x-2x = 8+2

x = 10

6 0
2 years ago
Avoiding an accident while driving can depend on reaction time. Suppose that reaction time, measured from the time the driver fi
Nadya [2.5K]

Answer:

2.5% of drivers have a reaction time more than 2.14 seconds

16% of drivers have a reaction time less than 1.78 seconds

84% of drivers have a reaction time less than 2.02 seconds

Step-by-step explanation:

The Empirical Rule(68-95-99.7 rule) states that, for a normally distributed random variable:

68% of the measures are within 1 standard deviation of the mean.

95% of the measures are within 2 standard deviation of the mean.

99.7% of the measures are within 3 standard deviations of the mean.

The normal distribution is symmetric, which means that 50% of the measures are below the mean and 50% are above.

In this problem, we have that:

Mean = 1.9s

Standard deviation = 0.12

What percentage of drivers have a reaction time more than 2.14 seconds?

2.14 = 1.9 + 2*0.12

So 2.14 is two standard deviations above the mean.

Of the 50% of the measures above the mean, 95% are within 2 standard deviations of the mean, so, below 2.14. The other 5% is above.

0.05*0.5 = 0.025

2.5% of drivers have a reaction time more than 2.14 seconds

What percentage of drivers have a reaction time less than 1.78 seconds?

1.78 = 1.9 - 0.12

So 1.78 is one standard deviation below the mean.

Of the 50% of the measures that are below the mean, 68% are within one standard deviation of the mean, that is, greater than 1.78.

100 - 68 = 32

0.32*50 = 0.16

16% of drivers have a reaction time less than 1.78 seconds

What percentage of drivers have a reaction time less than 2.02 seconds?

2.02 = 1.9 + 0.12

So 2.02 is one standard deviation above the mean.

Of the measures that are below the mean, all are below 2.02.

Of those that are above, 68% are below 2.02.

0.5 + 0.68*0.5 = 0.84

84% of drivers have a reaction time less than 2.02 seconds

5 0
3 years ago
Five people each take the same number of candies from a jar. Then a group of seven people does the same: in so doing they empty
Vika [28.1K]

Answer:

Step-by-step explanation:

Let first group of people take x candies each

and second group of people take y candies each

5x + 7y will be total candies

5x +7y = 239 (needed to find positive solution of x,y)

now take x=38,  y =7

or x=31,   y= 12

hence lots of possibilities ,so we can not say exactly

3 0
3 years ago
Read 2 more answers
Each lap around the track is 1/4 of a mile. How many laps will Quadir need to jog if he wants to jog 3 1/8 miles? Helpppp
weeeeeb [17]

9514 1404 393

Answer:

  12 1/2 laps

Step-by-step explanation:

To find the number of laps, divide the distance by the distance per lap.

  (3 1/8) ÷ (1/4) = (3 1/8) × (4/1) = 3·4 +(1/8)·4 = 12 4/8 = 12 1/2

Quadir needs to jog 12 1/2 laps if he wants to jog 3 1/8 miles.

5 0
3 years ago
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