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sergeinik [125]
3 years ago
14

COS2A+ cos2 A cot2A =cot 2 A

Mathematics
2 answers:
user100 [1]3 years ago
7 0

9514 1404 393

Explanation:

This is an identity.

  cos²(A) +cos²(A)cot²(A) = cot²(A)

Transforming the left side, we have ...

  = cos²(A)(1 +cot²(A))

  = cos²(A)csc²(A)

  = (cos(A)/sin(A))²

  = cot²(A)

Kryger [21]3 years ago
6 0

Answer:

a= (π/4) + (kπ/2)

Step-by-step explanation:

I have attached the explanation above. hopefully this will help

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Write as a equation how do I do this help plz
alisha [4.7K]

Answer:

41

Step-by-step explanation:

The two angles are vertical angles, so they are the same value.

(4x - 29) = (3x + 12)

<u>      +29            +29</u>  Moving terms around to solve the problem

 4x - 0   =  3x + 41

<u>-3x             -3x       </u>    Moving terms around to solve the problem

     x - 0 = 41

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6 0
3 years ago
A single conservative force vector F = (4.0x - 12)i hat N where x is in meters, acts on a particle moving along an x axis. The p
serious [3.7K]

Answer:

(4.0x - 12)i . (5/3)i

Step-by-step explanation:

Potential energy = Workdone

Workdone = Force x distance

Force = F = (4.0x - 12)i  N

Workdone = 20J

At  x= 0

F = -12i

/F/= 12

Workdone = Force  x distance

20  =   12 x   distance

Distance =  20/12

               =  5/3

In the vector form  distance is written as (5/3)i

Since Workdone/ Energy is scalar, U can be expressed as a dot product of  the vectors of Force and distance :

(4.0 x - 12)i . (5/3)i

7 0
3 years ago
PLEASE HELP! SUPER EASY
liubo4ka [24]

Answer:

1.trapezoid

parallelogram

3 0
3 years ago
PLS HELP, Rectangle A'B'C'D' is the image of rectangle ABCD under a dilation. Which calculation of the area of rectangle A'B'C'D
aev [14]
What grade of math is this? I’ll answer I just need to know cause a lot of chapters could be related to this
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3 years ago
Consider an unstructured overlay network in which each node randomly chooses c neighbors. If P and Q are both neighbors of R, wh
Fed [463]

The probability value become is 2c/(N-1).

According to the statement

we have given that If P and Q are both neighbors of R, and by considering unstructured network in which each node randomly chooses c neighbors.

we have to find that the probability of neighbors that they are also neighbors of each other.

So, For this purpose to find the probability is

Consider a network of N nodes unstructured and let

If each node chooses c neighbors at random,

then the probability that P will become by choose Q, or Q chooses P is roughly 2c/(N-1).

And the probability outcomes value become is 2c/(N-1).

So, The probability value become is 2c/(N-1).

Learn more about probability here brainly.com/question/25870256

#SPJ4

4 0
2 years ago
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