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3 years ago

COS2A+ cos2 A cot2A =cot 2 A

Mathematics

2 answers:

user100 [1]3 years ago

7 0

9514 1404 393

Explanation:

This is an identity.

cos²(A) +cos²(A)cot²(A) = cot²(A)

Transforming the left side, we have ...

= cos²(A)(1 +cot²(A))

= cos²(A)csc²(A)

= (cos(A)/sin(A))²

= cot²(A)

Kryger [21]3 years ago

6 0

Answer:

a= (π/4) + (kπ/2)

Step-by-step explanation:

I have attached the explanation above. hopefully this will help

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Please answer it in two minutes

ch4aika [34]

Answer:

67 in

Step-by-step explanation:

Because these are congruent figures, you know that the last remaining segment is 67in

3 0

3 years ago

A car travels at 65 miles per hour. Going through collision,it travels at 3/5 this speed. Write this fraction as a decimal.

solniwko [45]

Answer:

0.6

Step-by-step explanation:

the car moves at a speed of 3/5*65 miles per hour

that is 39 miles per hour

but this has nothing to do with the question as the only fraction is 3/5

6 0

3 years ago

Which shows 2-6 ///////////////////////////////////////////////////////

Leokris [45]

Answer:

Step-by-step explanation:

(1/2⁶)

7 0

2 years ago

Read 2 more answers

what is consecutive whole numbers? I have to write an algebraic expression for the sum of three consecutive whole numbers... :(

Agata [3.3K]

Answer:

Consecutive whole numbers (or integers) are numbers that directly follow one another.

Eg: 1, 2, 3, 4, 5 are consecutive whole numbers.

Step-by-step explanation:

Three consecutive even integers can be represented by x, x+2, x+4. The sum is 3x+6, which is equal to 108.

let the three consecutive whole numbers is x, x+1,and x+2

x + x+1 + x+2 = 4+2(x+1)

3x+3=4+2x+2

3x-2x=6-3

x=3

the other two numbers are 3+1=4,and 3+2=5

so the three numbers are 3,4 and 5

7 0

3 years ago

What are all of the real roots of the following polynomial? f(x) = x4 - 13x2 + 36

GREYUIT [131]

ANSWER

A. -3, -2, 2, and 3

EXPLANATION

The given polynomial function is,

$f(x) = {x}^{4} - 13 {x}^{2} + 36$

To find the real roots, we equate the function to zero to obtain;

${x}^{4} - 13 {x}^{2} + 36 = 0$

We can solve this equation as a quadratic equation in
${x}^{2}.$

Thus we rewrite the equation as,

$({x}^{2})^{2} - 13 {x}^{2} + 36 = 0$

We split the middle term to get,

$({x}^{2})^{2} - 9 {x}^{2} - 4 {x}^{2} + 36 = 0.$

We factor to get,

${x}^{2} ( {x}^{2} - 9) - 4( {x}^{2} - 9) = 0$

We factor to get,

$( {x}^{2} - 9)( {x}^{2} - 4) = 0$

Either

${x}^{2} - 9 = 0$
or

${x}^{2} - 4 = 0$

$x = \pm \sqrt{9} \: or \: x = \pm \sqrt{4}$
$x = \pm3 \: or \: x = \pm2$

$x=-3,-2,2,3$

The correct answer is A

5 0

3 years ago

Read 2 more answers