First aquarium dimensions:
Length = 6 m.
Width = 4 m and
Height = 2 meter.
Second aquarium dimensions:
Length = 8 m.
Width = 9 m and
Height = 3 meter.
We know formula for volume of a cuboidal box = Length*Width*Height.
Plugging values of length, width and height of first aquarium in formula of volume. We get
V1 = 6*4*2 = 48 m^3.
Plugging values of length, width and height of second aquarium in formula of volume. We get
V2 = 8*9*3 = 216 m^3.
In order to find the total cubic meters of space do the sea turtles have in their habitat, we need to add both volumes.
Therefore, Total voulme of both aquarium = V1 +V2 = 48+216 = 264 m^3.
Therefore, total 264 m^3 cubic meters of space the sea turtles have in their habitat.
The answer is 54.27. Hope I was halpful
Answer:
r≈5.36656314
Step-by-step explanation:
Since A=πr(r+
) so we get that 226.08/pi≈72 or 226.08/3.14=72 we then plug it in to get 72=r(r+
) so we get r≈5.36656314
Answer:
3
√
2
Explanation:
First put change the words into an equation:
√
3
×
√
6
Now you can multiply them together as you would normally multiply:
√
3
×
√
6
=
√
18
Now let's prime factor 18 and see if there are any squares that we can take out of it to simplify. All we have to see is if there are 2 numbers that are the same:
18
/ \
6
3
/ \
2
3
As you can see, we have a square:
3
×
3
=
9
So take
√
9
out of
√
18
. You should have:
√
9
√
2
But since
√
9
=
3
we can simplify further to make:
√
9
√
2
→
3
√
2
Step-by-step explanation:
