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1 year ago

For the triangle shown below, complete the following table.

Mathematics

1 answer:

Virty [35]1 year ago

6 0

Answer:

See below ~

Step-by-step explanation:

Sin A : opposing side of ∠A / hypotenuse

3/5

Sin C : opposing side of ∠C / hypotenuse

4/5

Cos A : adjacent side of ∠A / hypotenuse

4/5

Cos C : adjacent side of ∠C / hypotenuse

3/5

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How do you solve his with working

AlexFokin [52]

Check the picture below.

a)

so the perimeter will include "part" of the circumference of the green circle, and it will include "part" of the red encircled section, plus the endpoints where the pathway ends.

the endpoints, are just 2 meters long, as you can see 2+15+2 is 19, or the radius of the "outer radius".

let's find the circumference of the green circle, and then subtract the arc of that sector that's not part of the perimeter.

and then let's get the circumference of the red encircled section, and also subtract the arc of that sector, and then we add the endpoints and that's the perimeter.

$\bf \begin{array}{cllll}
\textit{circumference of a circle}\\\\ 
2\pi r
\end{array}\qquad \qquad \qquad \qquad 
\begin{array}{cllll}
\textit{arc's length}\\\\
s=\cfrac{\theta r\pi }{180}
\end{array}\\\\
-------------------------------$

$\bf \stackrel{\stackrel{green~circle}{perimeter}}{2\pi(7.5) }~-~\stackrel{\stackrel{green~circle}{arc}}{\cfrac{(135)(7.5)\pi }{180}}~+
\stackrel{\stackrel{red~section}{perimeter}}{2\pi(9.5) }~-~\stackrel{\stackrel{red~section}{arc}}{\cfrac{(135)(9.5)\pi }{180}}+\stackrel{endpoints}{2+2}
\\\\\\
15\pi -\cfrac{45\pi }{8}+19\pi -\cfrac{57\pi }{8}+4\implies \cfrac{85\pi }{4}+4\quad \approx \quad 70.7588438888$

b)

we do about the same here as well, we get the full area of the red encircled area, and then subtract the sector with 135°, and then subtract the sector of the green circle that is 360° - 135°, or 225°, the part that wasn't included in the previous subtraction.

$\bf \begin{array}{cllll}
\textit{area of a circle}\\\\ 
\pi r^2
\end{array}\qquad \qquad \qquad \qquad 
\begin{array}{cllll}
\textit{area of a sector of a circle}\\\\
s=\cfrac{\theta r^2\pi }{360}
\end{array}\\\\
-------------------------------$

$\bf \stackrel{\stackrel{red~section}{area}}{\pi(9.5^2) }~-~\stackrel{\stackrel{red~section}{sector}}{\cfrac{(135)(9.5^2)\pi }{360}}-\stackrel{\stackrel{green~circle}{sector}}{\cfrac{(225)(7.5^2)\pi }{360}}
\\\\\\
90.25\pi -\cfrac{1083\pi }{32}-\cfrac{1125\pi }{32}\implies \cfrac{85\pi }{4}\quad \approx\quad 66.75884$

7 0

3 years ago

In the pictures down below Can anyone help? Fractions and percents

wariber [46]

1st Picture:
$3)- \frac{6}{7} +\frac {10}{11}
\\\\LCD:77
\\\\\frac{6}{7}* \frac{11}{11} + \frac{10}{11}*\frac{7}{7}= \frac{66}{77} + \frac{70}{77} = \frac{136}{77} = 1\frac{59}{77} 
 \\ \\ 4) 3\frac{6}{7}* 2 \frac{1}{10}= \frac{27}{7} * \frac{21}{10} = \frac{567}{70} =\frac{81}{10} = 8\frac{1}{10}
\\\\5)2\frac{1}{2}+3\frac{1}{3}
\\\\LCD: 6
\\\\ 2\frac{3}{6} + 3\frac{2}{6} =5\frac{5}{6}
\\\\6)5\frac{1}{8}*-6\frac{6}{11}=\frac{41}{8}* \frac{72}{11}=\frac{2952}{88}=\frac{369}{11}=33\frac{6}{11}$

2nd Picture:

$1)80 percent of 80 = .8*80 =64
\\\boxed{64}
\\\\2)95percent of 100=.95*100=95
\\\boxed{95}$

7 0

3 years ago

Simplify <img src="https://tex.z-dn.net/?f=%28x%5E%7B2%7D%20%20%2B%203x%20-%204%29%20%2B%20%284%5E%7B2%7D%20%20-%205%29%

xxTIMURxx [149]

X^2-4x+4 is the answer, to save you points next time, use an app called M8thw8y

3 0

3 years ago

Read 2 more answers

A bird (b) is spotted flying 900 feet from an observer. the observer (o) also spots the top of a tower (t) at a height of 200 fe

Svetach [21]

Angle of depression = 12.52°

The right angle triangle formed has a height of 200 ft and a base of 900 ft.

The opposite side of the triangle is 200 ft while the adjacent side of the triangle is 900 ft.

Using tangential ratio we can find the angle of depression. Therefore,

Let

x = angle of depression

tan x = opposite/adjacent

opposite = 200 ft

adjacent = 900 ft

tan x = 200/900

tan x = 2/9

x = tan⁻¹ 2/9

x = tan⁻¹ 0.222

x = 12.5166739144

x = 12.52°

To learn more about angle of depression from the given link

brainly.com/question/16772926

#SPJ4

3 0

2 years ago

Please explain 22 and 23

ICE Princess25 [194]

Hey there!

$\bold{Mean\rightarrow your \ average}$
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