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snow_tiger [21]
3 years ago
8

A 5-digit number has the digits 0,5,7,9 and 0. To the nearest thousands, it rounds to 80,000. What is the number? Explain

Mathematics
2 answers:
Sloan [31]3 years ago
4 0
While when rounding go to the thousands and ten thousands , in this case. So... u want to have a number closest to the 8 without going over in the ten thousand place. That would be the 7.

The leftover numbers are 0,5,9, and 0. Now we want any number 5 or over in the thousands place. It could either be 5 or 9. I'm going to choose 9.

So far we have 79,??? The leftover numbers are 0,5, and 0. Now put the highest leftover number next... the 5. Then go ahead and put the two 0s at the end of the number.

Our answer would be 79,500. Rounded to the nearest ten thousand it would be 80,000.

HOPE THIS HELP:)      Please mark me as Brainliest if it helped u a lot!
Gnom [1K]3 years ago
3 0
Hey mate!
You stuck, huh?

A 5-digit number has the digits 0,5,7,9 and 0 could equal to, 79,500.
For you do understand why this number rounds to 80,000, we can take out the last 3 digits in each number. Therefore leaving you with, 79 an 80. As you can see, 79 can round to 80 because of it's value. Thus, you have your answer!

Hope this helps!
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If 65% of a number is 1105 what is 82% of the number
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Answer:

1394

Step-by-step explanation:

Set up equation to find the number:

Variable n = number

65/100 = 1105/n

Cross multiply:

65 × n = 100 × 1105

65n = 110,500

n = 1700

Check your work:

1700 × 65%

Convert percentage into decimal:

1700 × 0.65

1105

Correct!

Find 82% of 1700:

Variable x = 82% of 1700

82/100 = x/1700

82 × 1700 = 100 × x

139,400 = 100x

1394 = x

Check your work:

1700 × 82%

1700 × 0.82

1394

Correct!

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