1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
snow_tiger [21]
3 years ago
8

A 5-digit number has the digits 0,5,7,9 and 0. To the nearest thousands, it rounds to 80,000. What is the number? Explain

Mathematics
2 answers:
Sloan [31]3 years ago
4 0
While when rounding go to the thousands and ten thousands , in this case. So... u want to have a number closest to the 8 without going over in the ten thousand place. That would be the 7.

The leftover numbers are 0,5,9, and 0. Now we want any number 5 or over in the thousands place. It could either be 5 or 9. I'm going to choose 9.

So far we have 79,??? The leftover numbers are 0,5, and 0. Now put the highest leftover number next... the 5. Then go ahead and put the two 0s at the end of the number.

Our answer would be 79,500. Rounded to the nearest ten thousand it would be 80,000.

HOPE THIS HELP:)      Please mark me as Brainliest if it helped u a lot!
Gnom [1K]3 years ago
3 0
Hey mate!
You stuck, huh?

A 5-digit number has the digits 0,5,7,9 and 0 could equal to, 79,500.
For you do understand why this number rounds to 80,000, we can take out the last 3 digits in each number. Therefore leaving you with, 79 an 80. As you can see, 79 can round to 80 because of it's value. Thus, you have your answer!

Hope this helps!
You might be interested in
What is the answer for #2 only ? Thank you!! 5 points for these
mina [271]

Answer:

x=4.5 y=18.75

Step-by-step explanation:

solve using pythagorean theorem :

hypothenus²=opposite²+adjacent²

for y:

y²=15²+11.25²

y²=225+126.5625

y²=351.5625

y=18.75

for x:

7.5²=6²+x²

x²=7.5²-6²

x²= 56.25-36

x²=20.25

x=4.5

4 0
3 years ago
Please help me with this problem. I'm kind of stuck and don't know what to do.
Flauer [41]

Try this option:

1) if csc(u)=9, then 1/sin(u)=9 and sin(u)=1/9;

2) if sin(u)=1/9, then cos(u):

cos(u)=\sqrt{1-sin^2(u)}=\sqrt{1-\frac{1}{81}}=\frac{4\sqrt{5}}{9};

3) if \ sin(u)=\frac{1}{9} \ and \ cos(u)=\frac{4\sqrt{5}}{9}, then

sin(2u)=2sin(u)*cos(u)=\frac{8\sqrt{5}}{81};

cos(2u)=cos^2(u)-sin^2(u)=\frac{80}{81}-\frac{1}{81}=\frac{79}{81};

tan(2u)=\frac{sin(2u)}{cos(2u)}=\frac{\frac{8\sqrt{5}}{81}}{\frac{79}{81} }=\frac{8\sqrt{5}}{79}.

8 0
2 years ago
What is the answers to this
mash [69]
Answers to what exactly?
3 0
3 years ago
A book club charges a membership fee of $20 and then $12 for each book purchased. Write a function to represent the change, y, o
riadik2000 [5.3K]
It is y = 12x + 20.
You start with 20 as the y-intercept because that is the starting amount that you paid. The constant rate of change is 12 dollars per book. So, 12 time however many books written as 12x. Hope that helps! :)
4 0
3 years ago
Convert 12,5% to a decimal fraction.
Stolb23 [73]
Decimal fractions don't exist. Do you mean convert to a decimal and a fraction?
5 0
3 years ago
Other questions:
  • Can someone help me understand ? I’ve been having difficulties even though this looks very easy I feel like no one wants to help
    11·2 answers
  • Compare will mark bl
    8·2 answers
  • The perimeter of a rectangle is 256 inches. how long are the sides if the length exceeds the width by 16 inches? mark lets x rep
    7·2 answers
  • Please help me with this!
    13·1 answer
  • Which term is any number that can be shown as the quotient of two integers?
    5·1 answer
  • Which is another way to write the expression 23 • (p + 7)?
    15·1 answer
  • Which two numbers are not integers?
    6·2 answers
  • Pls answer quick rjwejriwejriwekr
    14·2 answers
  • Write and solve an equation to find the value of x. PLS HELP!!
    7·2 answers
  • If a finite set S of nonzero vectors spans a vector space V , then some subset of S is a basis for V . True or False
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!