While when rounding go to the thousands and ten thousands , in this case. So... u want to have a number closest to the 8 without going over in the ten thousand place. That would be the 7.
The leftover numbers are 0,5,9, and 0. Now we want any number 5 or over in the thousands place. It could either be 5 or 9. I'm going to choose 9.
So far we have 79,??? The leftover numbers are 0,5, and 0. Now put the highest leftover number next... the 5. Then go ahead and put the two 0s at the end of the number.
Our answer would be 79,500. Rounded to the nearest ten thousand it would be 80,000.
HOPE THIS HELP:) Please mark me as Brainliest if it helped u a lot!
A 5-digit number has the digits 0,5,7,9 and 0 could equal to, 79,500. For you do understand why this number rounds to 80,000, we can take out the last 3 digits in each number. Therefore leaving you with, 79 an 80. As you can see, 79 can round to 80 because of it's value. Thus, you have your answer!
The intersections of a transversal with two lines create various types of pairs of angles: consecutive interior angles, consecutive exterior angles, corresponding angles, and alternate angles.
