Answer:
AE = 15 cm; ED = 18 cm; AD = 15 cm (given)
Step-by-step explanation:
ΔBEC ~ ΔAED so ...
AD/BC = AE/BE = (BE+AB)/BE = 1 + AB/BE
Substituting given numbers (lengths in centimeters), we have ...
15/10 = 1 + 5/BE
1/2 = 5/BE
BE = 10
Similarly, ...
1/2 = 6/CE
CE = 12
Then the unknown sides are ...
AE = AB + BE = 5 + 10 = 15 . . . cm
ED = CE + CD = 12 + 6 = 18 . . . cm
The anwser is ten because the number i saw is 14 estimate is ten.
This is basically a simple problem to understand. The only thing that needs to be done is to divide the mass of the sun by the mass of mercury. It will give the required result.
Number of times the mass of sun is greater than
the mass of mercury = 21.3525×102921.3525×1029/<span>328.5×1021328.5×1021
= </span><span>7.1783629e+15
I hope that this is the answer that you were looking for and it has come to your great help.</span>
Answer:
Am I missing something to this question?
As pictured, the answer is 12 7/9ths.
You want to find R. From angle R, you know the side lengths for opposite and hypotenuse. According to SohCahToa, that is sine. Sin (x) = Opposite / Hypotenuse = 2.5 / 5 = 0.5
Sine(x)=.5. To get x by itself divide both by the inverse of sine.
