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koban [17]
2 years ago
13

A total of 42 gallons of a glycol solution needs to be added to a heating water loop to ensure the water does not freeze if ther

e is a heating equipment failure. The glycol solution comes in​ 1.75-gallon cans. How many cans will be​ needed? Your answer should be a whole number.
Mathematics
1 answer:
MArishka [77]2 years ago
4 0

Answer:

Number of cans of glycol solution needed = 24 cans

Step-by-step explanation:

Total glycol solution needed = 42 gallons

Volume of each can of glycol solution = 1.75 gallon

How many cans will be​ needed

Number of cans of glycol solution needed = Total glycol solution needed / Volume of each can of glycol solution

= 42 / 1.75

= 24

Number of cans of glycol solution needed = 24 cans

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Please help! / 50 points
lutik1710 [3]

Answer:

Solution given:

radius [r]=4

height [h]=5

we have

Surface area of cylinder=2πr(r+h)

=2π×4(4+5)

=<u>72πunits³ is a required volume.</u>

3 0
3 years ago
Can somebody help me with this. 35 points! :)))))
Vanyuwa [196]
HAIIII!!!! Your best option is C which shows 40 degrees!! I wish you best of luck
6 0
2 years ago
Complementary angles have measures (4x)° and (5x−27)°. find the measure of the larger angle.
Luda [366]

Answer:

4x=90

X=90÷4

X=22.5

5x-27=90

5x=90+27

5x=117

X=117÷5

X=23.4

So 23.4 is a larger angle

7 0
1 year ago
Find the area of the shaded region
AlexFokin [52]

Answer:

7\pi cm²

Step-by-step explanation:

First, find the area of the big circle with the formula A = \pir²

A = \pi(3)²

A = 9\pi

Now, we can find the areas of the smaller circles. Since they have the same radius, they are congruent (will have the same area)

A = \pir²

A = \pi(1)²

A = \pi

Now, we will subtract the areas of the smaller circles from the area of the big circle to find the area of the shaded region:

9\pi - \pi - \pi = 7\pi

So, the area of the shaded region is 7\pi cm²

5 0
3 years ago
Can someone please help me
faust18 [17]

Answer:

never

Step-by-step explanation:

smith will run out by week 2

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2 years ago
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