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g100num [7]
3 years ago
6

Billy is trying to convince Cynthia that all whole numbers are also natural numbers. To support his argument, Billy points out t

hat 1, 2, 3, 4, 5, and 6 are all whole numbers and are also natural numbers. He goes on to argue that, by continuing the pattern, every integer greater than 6 will also be both a whole number and a natural number, thus making all whole numbers natural numbers.
Mathematics
2 answers:
yaroslaw [1]3 years ago
7 0

Answer: The answer is B  have a good one #freedrakeo

Step-by-step explanation:

free ralphie

Temka [501]3 years ago
4 0

<span>He has failed to consider the number 0, which is a whole number but not a natural number.</span>
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Answer:

I am not exactly sure if im correct on this but i believe this answer is x = 1, y = 1

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Use the triangle below to find cos angle V​
ch4aika [34]

Answer:

\frac{2\sqrt{29} }{29}  last one

Step-by-step explanation:

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3 years ago
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Match the system of equations on the left with the appropriate solution on the right.
VARVARA [1.3K]

Answer:

x=7-2y        (1,3)

3x+6y=-9      (-1,-1)

4x-2y-3       \text{no solution}

2x+4y=7      \text{infinite number of solutions}

x=-2y-3     (1,-2)

Step-by-step explanation:

1:   x=7-2y

    \Rightarrow  x+2y=7

    \Rightarrow  (1,3)\;\text{is a solution of the above equation}.

2:    3x+6y=-9

      \Rightarrow  3(-1)+6(-1)=-3-6=-9

      \Rightarrow (-1,-1)\; \text{is a solution of the equation 3x+6y=-9}.

3:    4x-2y-3

      \Rightarrow  \;\text{It is not an equation}\\    \text{So, 4x-2y-3 has no solution.}

4:    2x+4y=7

     \Rightarrow  2x+4y=7\;\text{have an infinite number of solutions.}\\\text{Because for every x there exists a value of y which satisfies the equation.}

5:    x=-2y-3

     \Rightarrow x+2y=-3

     \Rightarrow  1-2(-2)=1-4=-3

    \Rightarrow (1,-2)\; \text{is a solution of the equation x=-2y-3}.

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3 years ago
Which polynomials are in standard form?
alekssr [168]
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The point stated to prove this point is:
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V is the 3D region enclosed by S. 

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Using cylindrical coords, ( rcos(θ), y, rsin(θ) ), dV=rdrdθdy 

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