Answer:
See the step-by-step explanation
Step-by-step explanation:
Let c be any element of C. (I'm not sure wether you have to assume that C is non-empt or not)
C is a subset of B. That means that as c is in C, it is also in B. (
)
Now, B is a subset of A. It follows that as
.
That means c is an element of A. The predicate Q is true for all elements of A, including c.
Because we let c be any element of C, we have proven that the predicate Q is true for all elements in C.
For the first question, all you need to know is that the (amount you want) divided by (the amount of cards total) is the probability of getting the amount you want at random. for example, if there are 3 red marbles in a bag of ten marbles, you divide 3 by 10 (0.30) the probability of picking up a red marble is 30%. try adding up how many cards you want to pick up by the number of cards total.
By expanding D it is clear that it is the factored form of 2/3x + 4
as 2/3x + 4 = 2/3x + 4*3/3
= 2/3x + (2*3)*(2/3). ( rearranging terms)
=2/3( x+ 2*3). ( taking 2*3 common)
=2/3( x + 6)
which is option D
hope it helped ^_^