Given the figure of a regular pyramid
The base of the pyramid is a hexagon with a side length = 6
The lateral area is 6 times the area of one of the side triangles
So, the side triangle has a base = 6
The height will be:
![\begin{gathered} h^2=6^2+(\frac{\sqrt[]{3}}{2}\cdot6)^2=36+27=63 \\ h=\sqrt[]{63} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20h%5E2%3D6%5E2%2B%28%5Cfrac%7B%5Csqrt%5B%5D%7B3%7D%7D%7B2%7D%5Ccdot6%29%5E2%3D36%2B27%3D63%20%5C%5C%20h%3D%5Csqrt%5B%5D%7B63%7D%20%5Cend%7Bgathered%7D)
so, the lateral area =
Answer: the length and width are
(x + 8) and (x + 8)
Step-by-step explanation:
The rug has an area represented by the expression
Area = 4x² + 64x + 256.
The factors in the factored expressions represent the length and width of the rug.
Dividing the the equation by 4, it becomes
x² + 16x + 64 = 0
We would find two numbers such that their sum or difference is 16x and their product is 64x^2.
The two numbers are 8x and 8x. Therefore,
x² + 8x + 8x + 64 = 0
x(x + 8) + 8(x + 8) = 0
The factors are
(x + 8)(x + 8)
Answer:
.
Step-by-step explanation:
Answer:
A. (9,-5)
Step-by-step explanation:
Translation down is -2 to the y coordinate, which is (5,-5). Then you translate it right 4 units, which is +4 to the x coordinate, so the final coordinate is (9,-5).