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Marta_Voda [28]

2 years ago

15

A wire is on the shape of a square of side 10 cm. If the wire is rebent into rectangle of length 12 cm, find its breadth. Which

encloses more area, the square or the rectangle?

1 answer:

frutty [35]2 years ago

4 0

Answer:

The square kase ahhh! Tag 12cm ang sides so same sila ng rectangle

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Use the following image to assist in your answer.<br> a =<br> - 6<br> - 9<br> - 4

vfiekz [6]

Step-by-step explanation:

Pythagoras' theorem for the smallest one :

$c^2 = 4^2 + 6^2$

$c^2 = 16 + 36$

$c^{2}$ = 52

Pythagoras' theorem for the middle one :

$b^{2}$ = $6^{2}$ + $a^{2}$

Pythagoras' theorem for the biggest one :

$(4+a)^2 = c^2 + b^2$

$16 + 8a + a^2 = 52 + b^2$

Using the formula before (for $b^2$ ) it becomes :

$16 + 8a + a^2 = 52 + (6^2 + a^2)$

$16 + 8a + a^2 = 52 + 6^2 + a^2$

$16 + 8a = 52 + 6^2$

16 + 8a = 52 + 36

16+8a = 88

8a = 88-16

8a = 72

$a = \frac{72}{8}$

a = 9

Verifying :

$b^2 = 6^2 + a^2$

$b^2 = 36 + 81$

$b^2 = 117$

$b^{2}$ = 117

The biggest one :

$(4+a)^2 = c^2 + b^2$

$(4+9)^2 = 52 + 117$

$13^2 = 169$

True

8 0

2 years ago

I need help with this specific math problem.

Anika [276]

Answer:

Example 1 Find the inverse transform of each of the following.

F

(

s

)

=

6

s

−

1

s

−

8

+

4

s

−

3

H

(

s

)

=

19

s

+

2

−

1

3

s

−

5

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7

s

5

F

(

s

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=

6

s

s

2

+

25

+

3

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G

(

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3

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12

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49

Show All Solutions

3 0

2 years ago

Find the distance between the two points rounding to the nearest tenth (if necessary).

ra1l [238]

Answer:

poit 1 5 q

Step-by-step explanation:

3 0

2 years ago

I don't get how to work out the repeating problems, could someone explain please?

barxatty [35]

Detecting...

Your answer would be:

$0.025 = 1/40 

0.025/1 * 1000/1000 = 25/1000

25 \div 25 / 1000 \div 25 = 1/40

1/40 is your answer.$

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2 years ago

X - 0.25x = 0.75x

MrRissso [65]

I have no idea myself

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3 years ago