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Marta_Voda [28]

2 years ago

15

A wire is on the shape of a square of side 10 cm. If the wire is rebent into rectangle of length 12 cm, find its breadth. Which

encloses more area, the square or the rectangle?

1 answer:

frutty [35]2 years ago

4 0

Answer:

The square kase ahhh! Tag 12cm ang sides so same sila ng rectangle

You might be interested in

Javier has a model of a cone with a radius of 3 inches and a height of 10 inches. Javier increased his model’s volume by doublin

statuscvo [17]

Answer:

$240 \pi\ in^{3}$

Step-by-step explanation:

we know that

If two figures are similar, then the ratio of its volumes is equal to the scale factor elevated to the cube

Let

z------> the scale factor

x-----> the volume of the larger cone

y-----> the volume of the original cone

$z^{3}=\frac{x}{y}$

In this problem we have

$z=2$ -----> scale factor

substitute

$2^{3}=\frac{x}{y}$

$8=\frac{x}{y}$

$x=8y$

That means-----> The volume of the larger cone is 8 times the volume of the original cone

Find the volume of the original cone

$V=\frac{1}{3}\pi r^{2} h$

we have

$r=3\ in$

$h=10\ in$

substitute

$V=\frac{1}{3}\pi (3^{2})(10)=30 \pi\ in^{3}$

therefore

The volume of the larger cone is equal to

$8*30 \pi\ in^{3}=240 \pi\ in^{3}$

3 0

3 years ago

Read 2 more answers

Okay have posted the next question.

Verdich [7]

Answer:

1. only 1 unique triangle can be made

2. only 1 unique triangle can be made

3. multiple triangles are possible

4. True

5. True

6. False

7. only 1 unique triangle can be made

8. only 1 unique triangle is possible

9. multiple triangles are possible

10. no triangle is possible

Step-by-step explanation:

Ask in comments if you got any questions.

8 0

3 years ago

Read 2 more answers

Hey can you please help me posted picture of question

Debora [2.8K]

We can use quadratic formula to determine the roots of the given quadratic equation.

The quadratic formula is:

$x= \frac{-b+- \sqrt{ b^{2} -4ac} }{2a}$

b = coefficient of x term = -11
a = coefficient of squared term = 2
c = constant term = 15

Using the values, we get:
$x= \frac{11+- \sqrt{121-4(2)(15)} }{2(2)} \\ \\ 
x= \frac{11+-1}{4} \\ \\ 
x=3, x= 2.5$

So, the correct answer to this question are option B and D

4 0

3 years ago

Urgent help needed. Will mark you brainlest when correct

posledela

Question 7: Option (4)

$A=(3/8)^2=\frac{9}{64}$

Question 8: Option (3)

$A=\frac{1}{2}(17)(9)=76.5$

Question 9: Option (2)

$A=\pi(10)^2 \approx 314$

7 0

2 years ago

<img src="https://tex.z-dn.net/?f=%20%5Cfrac%7Bx%7D%7B2%7D%20%2B1%20%3D%20%5Csqrt%7B3%7D%20" id="TexFormula1" title=" \frac{x}{2

Tresset [83]

I hope this helps you

3 0

3 years ago