That day they will have 132 conversations. There are 12 members and each one will be calling the remaining 11 members of the club which means each one will make 11 calls and that will be done by 12 members so 11x12= 132 conversations in total
12 months= 1 year
Every month they make 132 calls so 132x12 will be 1,584 calls per year.
If the club decides to add four new members to the club the conversations each month will rise up to 240.
If the other club likes the idea they can use the following equation
(x-1)(x)
X represents the number of members of the group the subtraction of 1 is when a member makes a call not including them selves so there are 12 members but the one making the call isn't included so there are 11 calls being made then being multiplied by the total number of members.
(x-1)(x)
(12-1)(12)
11(12)
132
-40 over 100, is the answer
the answer to your question is f=0
Answer:
The modulus of the complex number 6-2i is:
Step-by-step explanation:
Given the number
We know that
where x and y are real and 
The modulus or absolute value of z is:
Therefore, the modulus of will be:
Therefore, the modulus of the complex number 6-2i is:
