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zloy xaker [14]

2 years ago

11

The graph of quadratic parent function fwas transformed to create the graph of

1 answer:

Margarita [4]2 years ago

3 0

H is the correct answer. Y= (x+2)^2-5
2 to the left x+2=0 x=-2
5 dpwn

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The four hand of a clock moves from 12 to 5 o'clock through how many degrees does it move?

julsineya [31]

To find the answer you have to first find how many degrees are there in between each number in the clock. the clock is 360°degrees and there are 12 numbers marked in a clock., so you have to divide 360 by 12 to get the number of degrees in between each number,
360°÷12=30° so there are 30°degrees between each number.

if a clock hand moves from 12 to 5, it pass 5 numbers, so to get your final answer you have to multiply 30° by 5=150°.

so your answer is 150°degrees.
hope you can understand what i said. :)

8 0

3 years ago

Part B if the height of each prism is 10 Cm what is the surface area prism

Evgen [1.6K]

Answer:

Prism A:

$Area = 288cm^2$

Prism B:

$Area =250cm^2$

Step-by-step explanation:

Given

See attachment for prisms

$Height(h) = 10cm$

Required

Determine the surface area of both prisms

Prism A is triangular and as such, the surface area is:

$Area = 2 * A_b + (a + b + c) * h$

Where

$A_b = \sqrt{s * (s - a) * (s -b) * (s - c)}$

and

$s = \frac{a + b + c}{2}$

Such that a, b and c are the lengths of the triangular sides of the prism.

From the attachment;

$a = 8; b =6; c =10$

So, we have:

$s = \frac{a + b + c}{2}$

$s = \frac{8 + 6 + 10}{2}$

$s = \frac{24}{2}$

$s = 12$

Also:

$A_b = \sqrt{s * (s - a) * (s -b) * (s - c)}$

$A_b = \sqrt{12 * (12 - 8) * (12 - 6) * (12 - 10)}$

$A_b = \sqrt{576}$

$A_b = 24$

So:

$Area = 2 * A_b + (a + b + c) * h$

$Area = 2 * 24 + (8 + 6 + 10) * 10$

$Area = 288cm^2$

Prism B is a rectangular prism. So, the area is calculated as:

$Area = 2 * (ab + bh + ah)$

From the attachment

$a = b = 5$

$h =10$

So:

$Area =2 * (5 * 5 + 5 * 10 + 5 * 10)$

$Area =250cm^2$

7 0

2 years ago

Find the value of the expression w^3 if w= 7=

Tasya [4]

Answer
Substitute w by 7
7^3
7x7x7 =343

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Evaluate h(5t^{2})given that h(t)=17-11t

Gala2k [10]

$h(t)=17-11t$
$h(5t^{2})=17-11(5t^{2})$
$h(5t^{2})=17-55t^{2}$

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3 years ago

True or false, A function is a relation if and only if the x-values do not repeat in a given set

salantis [7]

Its false because it can't repeat in a set.

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