We can find the surface area of the pyramid as
![A = l*w+l*\sqrt{(\frac{w}{2} )^{2} +h^{2} }+w*\sqrt{(\frac{l}{2} )^{2} +h^{2}}](https://tex.z-dn.net/?f=A%20%3D%20l%2Aw%2Bl%2A%5Csqrt%7B%28%5Cfrac%7Bw%7D%7B2%7D%20%29%5E%7B2%7D%20%2Bh%5E%7B2%7D%20%7D%2Bw%2A%5Csqrt%7B%28%5Cfrac%7Bl%7D%7B2%7D%20%29%5E%7B2%7D%20%2Bh%5E%7B2%7D%7D)
here , because the base is squre so
![l = w = 8](https://tex.z-dn.net/?f=l%20%3D%20w%20%3D%208)
![h = 5](https://tex.z-dn.net/?f=h%20%3D%205)
By putting the values of l,w and h
we get
![A = 8*8+8*\sqrt{(\frac{8}{2} )^{2} +5^{2} }+8*\sqrt{(\frac{8}{2} )^{2} +5^{2}}](https://tex.z-dn.net/?f=A%20%3D%208%2A8%2B8%2A%5Csqrt%7B%28%5Cfrac%7B8%7D%7B2%7D%20%29%5E%7B2%7D%20%2B5%5E%7B2%7D%20%7D%2B8%2A%5Csqrt%7B%28%5Cfrac%7B8%7D%7B2%7D%20%29%5E%7B2%7D%20%2B5%5E%7B2%7D%7D)
![A = 64+8*\sqrt{16 +25 }+8*\sqrt{16 +25}](https://tex.z-dn.net/?f=A%20%3D%2064%2B8%2A%5Csqrt%7B16%20%2B25%20%7D%2B8%2A%5Csqrt%7B16%20%2B25%7D)
![A = 64+(8*\sqrt{41) +(8*\sqrt{41})](https://tex.z-dn.net/?f=A%20%3D%2064%2B%288%2A%5Csqrt%7B41%29%20%2B%288%2A%5Csqrt%7B41%7D%29)
![A = 64+51.2+51.2](https://tex.z-dn.net/?f=A%20%3D%2064%2B51.2%2B51.2)
![A = 166.4](https://tex.z-dn.net/?f=A%20%3D%20166.4)
In this item, we have:
A = 6x² + x +3
h = 3x
where ''A'' is area and ''h'' is height. From the statement above,
length of base, b = A / h
<em> b = (6x² + x + 3)/3x
</em>
Thus, the expression for the length of the base is 6x²+x+3 / 3x.
Answer:
*dies of boredom*
Step-by-step explanation:
EH, MWAH
Answer:
10 and 12 are two even integers whose product =120
Step-by-step explanation:
10 and 12 are two even integers whose product =120
![10\times 12=120](https://tex.z-dn.net/?f=10%5Ctimes%2012%3D120)
Answer:
δx=0.035 m
Step-by-step explanation:
We use the expression of the uncertainty of x:
δx = (x/(vo cosθ))*sqrt((cosθ)² (δV₀)²+(V₀ sinθ)²(δθ)² )
First of all, we need to identify δV₀ and δθ. In our case δV₀ = 0.002 m/s and δθ = 0.0175 rad.
Remember: 1° = 0.0175 rad. This is very important to get the right answer here.
Now, we just need to replace the values we have into the equation δx:
δx = (0.5/(3.49*cos(76)))*sqrt((cos(76))²*(0.02)²+(3.49*sin(76))²*(0.0175)²)
δx = 0.035 m.
Have a nice day!