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zalisa [80]
3 years ago
9

Write the phrase as an expression. Than evaluate when x=5. 6 more than the product of 8 and a number x.

Mathematics
1 answer:
scoundrel [369]3 years ago
6 0

8x+6     <<Expression


8x+6=

8*5+6=

40+6=

<h2><u>46  <<answer</u></h2>

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Solve for the variable p Write the equation 4l +26p= 210. Write the equation in the form p = an expression.
Fittoniya [83]

Answer:

p = (105-2l)/13

Step-by-step explanation:

4l + 26p = 210

Isolate 26p by subtracting 4l from both sides

26p = 210-4l now divide by 26

p = (210-4l)/26 you can simply

p = (105-2l)/13

8 0
3 years ago
14. BUS TRIP A bus leaves at 10 A.M. to take students on a field trip to a
k0ka [10]

The bus is 54.5 miles far from the site at the time of 11:30A.M as per the given information in the question.

<h3>What is the slope of a line?</h3>

The slope of a line indicates how steep it is. Slope is defined mathematically as "climb over run" (change in y divided by change in x).

It is assumed that a bus moving at a constant speed departs at 10 a.m. towards a historic location, is 100 miles away by 10:25 a.m., and is 65 miles away at 11:15 a.m.

We must create a point-slope equation that connects the distance from the place to the time in minutes after 10:00 a.m. Then, around 11:30 a.m., we need to figure out how far the bus is from the site.

A line's point-slope is y₂-y₁)=m(x₂-x₁)

Since x denotes the amount of minutes after 10:00 a.m., 10:25 a.m. is represented by x=25 and 11:15 a.m. by x=75.

At 10:25 a.m., a distance of 100 miles from the place is represented by 75.

The point represents a distance of 100 miles from the site at 10:25 a.m. The point represents a distance of 65 miles from the site at 11:15 a.m.

By substituting the points (25, 100) and (75, 65) into the slope formula and simplifying we get,

m=(y₂-y₁)/(x₂-x₁)

m=(65-100)/(75-25)

m=-35/50

m=-0.7

Now choose one of the points and substitute that point and the slope into the slope-point form

y₋y₁=m(x-x₁)

By choosing (x₁, y₁)=(25, 100)

By choosing (x₂, y₂)=(75, 65)

Since 11:30 A,M is 90 minutes after 10:00A.M

By substituting x=90 in the equation we get the value of y,

y-100= -0.7(90-25)

y-100= -0.7(65)

y-100 =-45.5

y= 54.5

Hence, the bus is 54.5 miles from the site at the time of 11:30 A.M

y-100= -0.7(x-25)

OR

y-65= -0.7(x-75)

The bus is 54.5 miles from the site at 11:30A.M.

To know more about slope of a line, visit:

brainly.com/question/28771374

#SPJ9

6 0
2 years ago
PLEASE HELP!! (Look at photo)
Mila [183]

Answer:

C

10 x (p+2) = 30

10 x 2 = 20 30 - 20 = 10 10 ÷ 10 = 1

P = 1

10 x (1 + 2) = 30

5 0
3 years ago
Find the value of x.
Aneli [31]

Answer:

39x

Step-by-step explanation:

3 0
3 years ago
A psychological study found that men who were distance runners lived, on average, five years longer than those who were not dist
poizon [28]

Answer:

1. There is  not enough evidence to support the claim that men who were distance runners lived, on average, five years longer than those who were not distance runners.

2. The test statistic is t.

Step-by-step explanation:

<em>The question is incomplete:</em>

  1. <em>Test the claim that men who were distance runners lived, on average, five years longer than those who were not distance runners.</em>
  2. <em>Which of the following is the test statistic for the appropriate test to  determine if men who are distance runners live significantly longer, on  average, than men who are not distance runners?</em>

The test statistic is t, as this is a t-test for the difference of means.

The claim is that men who were distance runners lived, on average, five years longer than those who were not distance runners.

Then, the null and alternative hypothesis are:

H_0: \mu_1-\mu_2=5\\\\H_a:\mu_1-\mu_2> 5

The significance level is 0.05.

The sample 1, of size n1=50 has a mean of 84.2 and a standard deviation of 10.2.

The sample 1, of size n1=30 has a mean of 79.2 and a standard deviation of 6.8.

The difference between sample means is Md=5.

M_d=M_1-M_2=84.2-79.2=5

The estimated standard error of the difference between means is computed using the formula:

s_{M_d}=\sqrt{\dfrac{\sigma_1^2}{n_1}+\dfrac{\sigma_2^2}{n_2}}=\sqrt{\dfrac{10.2^2}{50}+\dfrac{6.8^2}{30}}\\\\\\s_{M_d}=\sqrt{2.081+1.541}=\sqrt{3.622}=1.903

Then, we can calculate the t-statistic as:

t=\dfrac{M_d-(\mu_1-\mu_2)}{s_{M_d}}=\dfrac{5-5}{1.903}=\dfrac{0}{1.903}=0

The degrees of freedom for this test are:

df=n_1+n_2-1=50+30-2=78

This test is a right-tailed test, with 78 degrees of freedom and t=0, so the P-value for this test is calculated as (using a t-table):

P-value=P(t>0)=0.5

As the P-value (0.5) is bigger than the significance level (0.05), the effect is not significant.

The null hypothesis failed to be rejected.

There is  not enough evidence to support the claim that men who were distance runners lived, on average, five years longer than those who were not distance runners.

6 0
3 years ago
Read 2 more answers
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