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Elina [12.6K]
3 years ago
10

Negative square root of nine is it a rational or irrational number

Mathematics
2 answers:
Sergio [31]3 years ago
7 0

It's a rational number. 9 is a perfect square. What you have asked is written as -sqrt(9), which can be written as -sqrt(3*3) which is - 3. That's perfectly OK. What would not be OK is something like -sqrt(10) which is irrational because it cannot be represented as a fraction or a whole number or a repeating decimal or a decimal that terminates.

alina1380 [7]3 years ago
4 0

The negative square root of nine is neither rational or irrational.

The answer to this problem is 3i, which is an imaginary number. Imaginary numbers, by definition, are neither rational or irrational.

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What are the roots of the function f(x) = x2 + 2x – 1? a. x = ± √ _ 2 b. x = − 1 ± √ _ 2 c. x = 2 ± √ _ 2 d. x = 1 ± √ _ 2
Masteriza [31]

Step-by-step explanation:

Root of the function, where y = 0

f(x) = x² + 2x - 1

0 = x² + 2x - 1

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Drag each tile to the correct box. Each tile shows an investor's tax bracket along with the tax-free yield of a bond the investo
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<h3>Taxable equivalent yield based problem:</h3>

The taxable equivalent yield will be:

= Tax-free yield / (100 - Tax bracket)

Taxable equivalent yield =  3 / (100 - 18) = 0.03659

Taxable equivalent yield = 6 / (100 - 24) = 0.07895

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2 years ago
Find the value of x² - x+1 when x=√3 -1, in the form a+b√3 where a and b are integers​
lidiya [134]

Answer:

6-3\sqrt{3}

If you compare this to a+b\sqrt{3}, then a=6 and b=-3.

Step-by-step explanation:

We are given x=\sqrt{3}-1 and we are asked to find the value of x^2-x+1.

So we will need to find x^2.

x=\sqrt{3}-1

Square both sides:

x^2=(\sqrt{3}-1)^2

Expand using identity: (x-a)^2=x^2-2ax+a^2.

x^2=(\sqrt{3})^2-2(\sqrt{3})(1)+1^2

x^2=3-2\sqrt{3}+1

x^2=4-2\sqrt{3}

Let's go back to the full x^2-x+1.

x^2-x+1

(4-2\sqrt{3})-(\sqrt{3}-1)+1

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6-3\sqrt{3}

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3 years ago
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