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kotegsom [21]
3 years ago
10

A bag contains 3 red balls and 2 blue balls. A ball is taken at random from the bag and then put back. And then a second ball is

then taken out of the bag. The probability tree for this situation is shown below. What is the probability of getting 2 red or 2 blue balls?
Question 7 options:


.52


.36


.16


.2
Mathematics
1 answer:
mrs_skeptik [129]3 years ago
5 0
6 balls in the bag
1/6 getting the random color
1/6=about .16
so C
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EESE p() = 35/59 * 34/58 * 24/57 * 33/56 =

ESEE p() = 35/59 * 24/58 * 34/57 * 33/56 =

SEEE p() = 24/59 * 35/58 * 34/57 * 33/56 =

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ESES p() = 35/59 * 24/58 * 34/57 * 23/56 =

SEES

SESE

SSEE

ESSS  And so on, but...a big BUT...why do all this when

SESS

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Step-by-step explanation:

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