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harina [27]
3 years ago
6

A manufacturer of shipping boxes has a box shaped like a cube. The side length is (5a + 4b). What is the volume of the box in te

rms of a and b? Show your work.
Mathematics
1 answer:
rodikova [14]3 years ago
7 0
<span>Volume of a square = (s)(s)(s) and s=5a+4b Therefore: (5a+4b)(5a+4b)(5a+4b)= (25a^2+40ab+16b^2)(5a+4b)= (125a^3+200a^2b+80ab^2+100a^2b+160ab^2+64b^3)= (125a^3+300a^2b+240ab^2+64b^3) You just multiple the first time the second and then do so again with the combination of the first two times the second. A little cleaning up and you are left with an equation in terms of a and b.</span>
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Anyone can help me with math for solving for a side in the right triangles for khan academy
Elden [556K]

Answer:

7.45

Step-by-step explanation:

We are given a right triangle with one side length known and an angle know so we can use some trigonometry.

You need to find the hypotenuse so you are going to use either sine or cosine.

Since the adjacent from the angle is given (SOH-CAH-TOA) we can use cosine so,

cos(20) = 7/h

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6 0
3 years ago
Help me answer please
fiasKO [112]

Answer:

25

Step-by-step explanation:

b=4x+1    h=x+1     A=175

A=bh

Substitute: 175=(4x+1)(x+1)

Expand: 175=4x^2+5x+1

Subtract 175

4x^2+5x-174=0

Solve w/quadratic formula

(-5 <u>+</u> sqrt(25+2784))/8

Simplify: x=6 or -29/4

Distance is positive, so x=6

4x+1=4*6+1=25


6 0
3 years ago
A balloon is rising at a constant speed of 5 ftys. A boy is cycling along a straight road at a speed of 15 ftys. When he passes
Ket [755]

Answer:

  13 ft/s

Step-by-step explanation:

t seconds after the boy passes under the balloon the distance between them is ...

  d = √((15t)² +(45+5t)²) = √(250t² +450t +2025)

The rate of change of d with respect to t is ...

  dd/dt = (500t +450)/(2√(250t² +450t +2025)) = (50t +45)/√(10t² +18t +81)

At t=3, this derivative evaluates to ...

  dd/dt = (50·3 +45)/√(90+54+81) = 195/15 = 13

The distance between the boy and the balloon is increasing at the rate of 13 ft per second.

_____

The boy is moving horizontally at 15 ft/s, so his position relative to the spot under the balloon is 15t feet after t seconds.

The balloon starts at 45 feet above the boy and is moving upward at 5 ft/s, so its vertical distance from the spot under the balloon is 45+5t feet after t seconds.

The straight-line distance between the boy and the balloon is found as the hypotenuse of a right triangle with legs 15t and (45+5t). Using the Pythagorean theorem, that distance is ...

  d = √((15t)² + (45+5t)²)

7 0
3 years ago
Use inverse operations to solve the equation <br><br> a - 5/6 = - 3 2/3
larisa [96]

Answer:

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4 0
3 years ago
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