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harina [27]
3 years ago
6

A manufacturer of shipping boxes has a box shaped like a cube. The side length is (5a + 4b). What is the volume of the box in te

rms of a and b? Show your work.
Mathematics
1 answer:
rodikova [14]3 years ago
7 0
<span>Volume of a square = (s)(s)(s) and s=5a+4b Therefore: (5a+4b)(5a+4b)(5a+4b)= (25a^2+40ab+16b^2)(5a+4b)= (125a^3+200a^2b+80ab^2+100a^2b+160ab^2+64b^3)= (125a^3+300a^2b+240ab^2+64b^3) You just multiple the first time the second and then do so again with the combination of the first two times the second. A little cleaning up and you are left with an equation in terms of a and b.</span>
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Which of the following is not one of the 8th roots of unity?
Anika [276]

Answer:

1+i

Step-by-step explanation:

To find the 8th roots of unity, you have to find the trigonometric form of unity.

1.  Since z=1=1+0\cdot i, then

Rez=1,\\ \\Im z=0

and

|z|=\sqrt{1^2+0^2}=1,\\ \\\\\cos\varphi =\dfrac{Rez}{|z|}=\dfrac{1}{1}=1,\\ \\\sin\varphi =\dfrac{Imz}{|z|}=\dfrac{0}{1}=0.

This gives you \varphi=0.

Thus,

z=1\cdot(\cos 0+i\sin 0).

2. The 8th roots can be calculated using following formula:

\sqrt[8]{z}=\{\sqrt[8]{|z|} (\cos\dfrac{\varphi+2\pi k}{8}+i\sin \dfrac{\varphi+2\pi k}{8}), k=0,\ 1,\dots,7\}.

Now

at k=0,  z_0=\sqrt[8]{1} (\cos\dfrac{0+2\pi \cdot 0}{8}+i\sin \dfrac{0+2\pi \cdot 0}{8})=1\cdot (1+0\cdot i)=1;

at k=1,  z_1=\sqrt[8]{1} (\cos\dfrac{0+2\pi \cdot 1}{8}+i\sin \dfrac{0+2\pi \cdot 1}{8})=1\cdot (\dfrac{\sqrt{2}}{2}+i\dfrac{\sqrt{2}}{2})=\dfrac{\sqrt{2}}{2}+i\dfrac{\sqrt{2}}{2};

at k=2,  z_2=\sqrt[8]{1} (\cos\dfrac{0+2\pi \cdot 2}{8}+i\sin \dfrac{0+2\pi \cdot 2}{8})=1\cdot (0+1\cdot i)=i;

at k=3,  z_3=\sqrt[8]{1} (\cos\dfrac{0+2\pi \cdot 3}{8}+i\sin \dfrac{0+2\pi \cdot 3}{8})=1\cdot (-\dfrac{\sqrt{2}}{2}+i\dfrac{\sqrt{2}}{2})=-\dfrac{\sqrt{2}}{2}+i\dfrac{\sqrt{2}}{2};

at k=4,  z_4=\sqrt[8]{1} (\cos\dfrac{0+2\pi \cdot 4}{8}+i\sin \dfrac{0+2\pi \cdot 4}{8})=1\cdot (-1+0\cdot i)=-1;

at k=5,  z_5=\sqrt[8]{1} (\cos\dfrac{0+2\pi \cdot 5}{8}+i\sin \dfrac{0+2\pi \cdot 5}{8})=1\cdot (-\dfrac{\sqrt{2}}{2}-i\dfrac{\sqrt{2}}{2})=-\dfrac{\sqrt{2}}{2}-i\dfrac{\sqrt{2}}{2};

at k=6,  z_6=\sqrt[8]{1} (\cos\dfrac{0+2\pi \cdot 6}{8}+i\sin \dfrac{0+2\pi \cdot 6}{8})=1\cdot (0-1\cdot i)=-i;

at k=7,  z_7=\sqrt[8]{1} (\cos\dfrac{0+2\pi \cdot 7}{8}+i\sin \dfrac{0+2\pi \cdot 7}{8})=1\cdot (\dfrac{\sqrt{2}}{2}-i\dfrac{\sqrt{2}}{2})=\dfrac{\sqrt{2}}{2}-i\dfrac{\sqrt{2}}{2};

The 8th roots are

\{1,\ \dfrac{\sqrt{2}}{2}+i\dfrac{\sqrt{2}}{2},\ i, -\dfrac{\sqrt{2}}{2}+i\dfrac{\sqrt{2}}{2},\ -1, -\dfrac{\sqrt{2}}{2}-i\dfrac{\sqrt{2}}{2},\ -i,\ \dfrac{\sqrt{2}}{2}-i\dfrac{\sqrt{2}}{2}\}.

Option C is icncorrect.

5 0
3 years ago
A bank is offering 7% annual compound interest on a savings account. If you deposit $1,500, what will be the total amount of mon
Nimfa-mama [501]
1,837.56 is the answer!
6 0
3 years ago
The proof diagram to complete the question state the missing reason in the proof for the letter given
melisa1 [442]

ANSWER

First proved that line p is parallel to line r

to proof

As given in the question

∠1 ≈∠5

∠1 and ∠5 are corresponding angles

by using the property of the corresponding angles

 two lines are cut by a transversal so that the corresponding angles are


congruent, then these lines are parallel.


As shown in diagram q is transversal line.

Thus by using the above property

line p is parallel to line r.

proof of 1(a)

REASON

Vertically opposite angle

The pair of angles formed when two lines intersect each other are called vertically opposite angles.

Thus

∠4 and ∠1 are vertically opposite angle

thus

∠4 ≈∠ 1

proof of 2(b)

REASON

Alternate interior angle

the pairs of angles on either side of the transversal and inside the two lines are called the alternate interior angles . If two parallel lines are cut by a transversal, then the alternate interior angles formed are congruent .

as line p is parallel to line r (proof above)

q is transversal

thus

∠4 ≈∠ 5

Hence proved

proof of 3 (c)

As ∠4 ≈∠5 (proof above)  

REASON

If two lines are cut by a transversal so that the alternate interior angles

are congruent, then these lines are parallel.

Thus by above property

line p is parallel to line r

Hence proved







4 0
3 years ago
Read 2 more answers
What number is the same as 3 tens + 10 ones?
mamaluj [8]
3 tens= 30
10 ones= 10
30+10=40
6 0
3 years ago
Read 2 more answers
Please HELP I DONT KNOW WHTA IM DOING!!
trasher [3.6K]
BD is 18

XY is 4

IK is 8

DF is 16
6 0
3 years ago
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